Find the circumference of a circle that has an area of 452.16 square meters. (Use 3.1416 as the value of π.) A. 37.6992 meters B
2 answers:
You might be interested in
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
10 cm
Step-by-step explanation:
Given:
No. of small spherical bulb = 1,000
radius (r) of smaller bulbs = 1 cm
Required:
radius of the bigger bulb
SOLUTION:
The following equation represents the relationship of the volume of the smaller and bigger bulb,
Where,
= volume of bigger bulb
= volume of smaller bulb
1,000 is the number of smaller bulbs melted to form the bigger bulb.
Volume of a sphere is given as, ⁴/3πr³
Therefore:
= ⁴/3*π*r³ = 4πr³/3
= ⁴/3*πr³ = ⁴/3*π*(1)³ = ⁴/3π*1 = 4π/3
Plug the above values into the equation below:
(12pie cancels 12 pie)
(taking the cube root of each side)
Radius of the bigger bulb = 10 cm