<u>Answer:</u>
Consistent and dependent
<u>Step-by-step explanation:</u>
We are given the following equation:
1. 
2. 
3. 
For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with
which is the same as the equation number 2.
There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.
Answer:
12 squares
Step-by-step explanation:
Data provided:
Dimension of the rectangle = 30 × 40
Area of the rectangle = 30 × 40 = 1200
Dimension of the area to be divided = 10 × 10
Thus,
Area of the square to be divided into = 100
Therefore,
The number of square in which it can be divided
=
=
= 12
Hence,
It can be divided in 12 squares
Answer:
![\dfrac{\sqrt[5]{810x^3}}{3x}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B5%5D%7B810x%5E3%7D%7D%7B3x%7D)
Step-by-step explanation:
As a rule, the "simplified form" means there are no fractions under a radical.
![\sqrt[5]{\dfrac{10x}{3x^3}}=\sqrt[5]{\dfrac{10x(3^4x^2)}{3x^3(3^4x^2)}}=\sqrt[5]{\dfrac{810x^3}{(3x)^5}}=\boxed{\dfrac{\sqrt[5]{810x^3}}{3x}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%5Cdfrac%7B10x%7D%7B3x%5E3%7D%7D%3D%5Csqrt%5B5%5D%7B%5Cdfrac%7B10x%283%5E4x%5E2%29%7D%7B3x%5E3%283%5E4x%5E2%29%7D%7D%3D%5Csqrt%5B5%5D%7B%5Cdfrac%7B810x%5E3%7D%7B%283x%29%5E5%7D%7D%3D%5Cboxed%7B%5Cdfrac%7B%5Csqrt%5B5%5D%7B810x%5E3%7D%7D%7B3x%7D%7D)
Answer:
We can say that the given equation has no extraneous solutions.
The correct option is A.) 0
Step-by-step explanation:
the given equation is 
this equals to 
therefore 
Solving the equation through Newton-Raphson method we get n
2.3845.
We can say that the given equation has no extraneous solutions.