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Leno4ka [110]
2 years ago
6

The box-and-whisker plot below shows the age distribution of people at a family reunion. A box-and-whisker plot is shown. The nu

mber line goes from 8 to 72 in increments of 8. The whiskers range from 8 to 71, and the box ranges from 23 to 47. A line divides the box at 38. The stem-and-leaf plot below shows the same data. A stem and leaf plot is shown. The stems from top to bottom are 0, 1, 2, 3, 4, 5, 6, 7. The first column of leaves is 8, 0, 3, 1, 0, 0, 0. The second column of leaves is 9, 1, 3, 6, 1, 2, 1. The third column of leaves is blank, 4, 5, 6, 2, 3, blank. The fourth column of leaves is blank, 5, 6, 8, 4, 6, blank. The fifth column of leaves is blank, blank, 6, 9, 6, blank, blank. The sixth column of leaves is blank, blank, blank, 9, blank, blank, blank. The seventh column of leaves is blank, blank, blank, 9, blank, blank, blank.
Mathematics
2 answers:
marishachu [46]2 years ago
6 0

Answer:

its b i think

Step-by-step explanation:

Setler79 [48]2 years ago
5 0

Answer:

The answer is C

Step-by-step explanation:

got it right on edge

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Speed= 100 rev/1 min=(1/4rev)/x min

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2 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

7 0
2 years ago
KC has a piece of gum stuck to her bike tire, which applies a forward torque (i.e. a force to roll forwards) on the tire's movem
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Answer:

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