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2 years ago

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Bipasha can eat 24 rasgullas in 12 minutes. Her friend Sujata takes DOUBLE the time to eat the same number.One day they buy 24 r

asgullas and start eating them. If they eat at their normal speeds till the rasgullas are over, how many rasgullas would Sujata have eaten?

1 answer:

Crazy boy [7]2 years ago

5 0

Answer:

12

Step-by-step explanation:

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ABCD ~ EFGH<br> z=?<br> Please help me!!!

iragen [17]

Answer:

z = 110°

Step-by-step explanation:

Since the figures are similar, then corresponding angles are congruent, thus

∠H = ∠D, that is

z = 110°

5 0

2 years ago

The ratio of the perimeter of square RSTU to the perimeter of square WXYZ is 1 to 3. The area of square RSTU is 36 square inches

Ainat [17]

√36 square inches = 6 inches (length of sq RSTU)
6 inches x 4=24 inches (per. of sq RSTU)
-----------------------------------
1u=24 inches
3u=24 inches x 3=72 inches (per. of sq WXYZ)
-----------------------------------
72 inches ÷ 4=18 inches (length of sq WXYZ)
18 inches x 18 inches = 324 square inches( area of sq WXYZ)

Ans: 324 square inches

5 0

2 years ago

Read 2 more answers

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

<em>Point a:</em>

The Expected value or the mean value of X with set of possible values D, denoted by <em>E(X)</em> or <em>μ </em>is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by <em>E[h(X)]</em> is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

<em>Point b:</em>

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and <em>E(X)</em> = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

2 years ago

A kite string is being held 3 ft above the ground. The string is 185 ft long and is flying at an angle of elevation of 36° . Wha

-Dominant- [34]

500 let me know if it’s right i’m not the best at math

8 0

2 years ago

The amount of water that the girls on the basketball and soccer teams drink during one practice session is recorded in the dot p

Radda [10]

Answer:

<h2>B. 30 oz less than.</h2>

Step-by-step explanation:

We have two dot plots, one for the Basketball Team and one for the Soccer Team.

Notice that there are 16 girls in the Basketball Team and 16 girls in the Soccer Team.

Basically, the median is between the 8th and 9th term in each data set. Specifically, is the mean between them.

<h3>For Basketball Team</h3>

$m_{basketball} =\frac{32+32}{2}=32$

Because the 8th and 9th term are both equal to 32.

<h3>For Soccer Team</h3>

$m_{soccer}=\frac{64+64}{2}=64$

Because the 8th and 9th term are both equal to 64.

If we subtract them to find the difference, it would be

$\Delta m=64-32=32$

Basically, the Soccer Team drank 32 more ounces of water than the Basketball Team.

Therefore, the right answer is B, that's the closest one.

4 0

2 years ago

Read 2 more answers