In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66. What
julia-pushkina [17]
Answer:
The 65th percentile is between 73 and 74
Step-by-step explanation:
Rearrange the ungrouped data in ascending order: 65,66,67,68,71,73,74,77,77,77
The 65th percentile is 65/100 of N ( N = 10) = 65/100 × 10 = 6.5
The 65th percentile is the 6.5th term. The 6th term is 73 and the 7th term is 74, the 6.5th term is between the 6th and 7th term
The 65th percentile is between 73 and 74
Possibilities of outcomes:
5, 5, 5
5, 5, 4
P(sum at least 14) = P(5,5,4) + P(5,5,5)
= 1/4 x 1/4 x 3/20 + 1/4 x 1/4 x 1/4
1/40
Hello,
<span>We have that:
(4x+10)+(2x-1)=9x-15
</span>We solve the equation:
4x+10+2x-1=9x-15;
6x+9=9x-15;
6x-9x=-15-9;
-3x=-24;
3x=24;
<span>from which
</span>x=24:3=8
<span>Then:
DF=9x-15=(9</span>×8)-15=72-15=57
bye :-)
Answer:I can’t see the rest.
Step-by-step explanation:
Answer:
Option 3 is right.
Step-by-step explanation:
Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.
In whatever way we find reference angles,
cos will remain cos only and sin will remain sin only there may be only changes in sign.
Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos. Hence these options cannot be for reference angles.
III option is 
show that both sign and cos changed sign. This is possible only in III quadrant.
ie reference angle of orignal angle t = 180+t
SO this option is right.