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1 year ago

11

Bipasha can eat 24 rasgullas in 12 minutes. Her friend Sujata takes DOUBLE the time to eat the same number.One day they buy 24 r

asgullas and start eating them. If they eat at their normal speeds till the rasgullas are over, how many rasgullas would Sujata have eaten?

1 answer:

Crazy boy [7]1 year ago

5 0

Answer:

12

Step-by-step explanation:

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Alvin and Bala has 26 stickers.Alvin had 8 more stickers thab Bala.How many stickers did Bala have?

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Bala had 9 stickers

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You must now isolate x by first subtraction 8 from both sides which will leave you with 2x=18. Then you divide on both sides by 2 and will leave you with x=9

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2 years ago

2x+5y=-6 , wht is the x intercept, what is the y intercept

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2 years ago

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2 years ago

Meeting at least one person with the flu in thirteen random encounters on campus when the infection rate is 2% (2 in 100 people

s344n2d4d5 [400]

Answer:

23.1% probability of meeting at least one person with the flu

Step-by-step explanation:

For each encounter, there are only two possible outcomes. Either the person has the flu, or the person does not. The probability of a person having the flu is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Infection rate of 2%

This means that $p = 0.02$

Thirteen random encounters

This means that $n = 13$

Probability of meeting at least one person with the flu

Either you meet none, or you meet at least one. The sum of the probabilities of these outcomes is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{13,0}.(0.02)^{0}.(0.98)^{13} = 0.7690$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.769 = 0.231$

23.1% probability of meeting at least one person with the flu

6 0

1 year ago