Ask question

Ask question

All categories

2 years ago

13

Your grandparents send you a check for $150 for your birthday. You deposit the check into your savings account which has a balan

ce of $1,255. How much money will you expect to have in your account in one year if the interest rate is 2.5% and you don’t take any money out?

1 answer:

NNADVOKAT [17]2 years ago

4 0

313.75 I believe that is the correct answer or som

You might be interested in

Joe's Painting charges $100 plus $20 per hour to paint the exterior of your home. Steve's Painting charges $120 plus $15 per hou

Tanzania [10]

Joe's Painting: 20x + 100 = y

Steve's Painting: 15x + 120 = y

x = hours worked

y = total income

We can find when the two equations intersect by making them equal to each other. That means we put an equal sign in the middle. So, it would look something like this:

20x + 100 = 15x + 120

First, we have to move the 100 by subtracting it from both sides.

20x = 15x + 120 - (100)

20x = 15x + 20

Then, we need to move the 15x by subtracting it from both sides.

20 - (15x) = 20

5x = 20

Lastly, we need to divide 5 from both sides.

5x = 20/5

x = 4

Therefore, Joe and Steve would have to work for 4 hours in order for their models to be equal to each other.

5 0

2 years ago

Maya scored 32 out of 40 for a Math's test and 41 out of 55 for a science's test. For which test did she score a lower percentag

Alex777 [14]

Answer:

He score lower on the 41 out of 55

Step-by-step explanation:

32/40 = .80 or 80%

41/55 = 0.75 or 75%

4 0

1 year ago

Read 2 more answers

Seventy cards are numbered 1 through 70, one number per card. One card is randomly selected from the deck. What is the probabili

miskamm [114]

Given:

Seventy cards are numbered 1 through 70, one number per card. One card is randomly selected from the deck.

To find:

The probability that the number drawn is a multiple of 3 and a multiple of 5.

Solution:

Total number from 1 to 70 = 70

Multiple of 3 from 1 to 70 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69.

Multiple of 5 from 1 to 70 are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70.

Numbers which are multiply of both number 3 and 5 = 15, 30, 45, 60

Number of favorable outcomes = 4

$Probability=\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

$Probability=\dfrac{4}{70}$

$Probability=\dfrac{2}{35}$

Therefore, the required probability is $\dfrac{2}{35}$ .

7 0

1 year ago

Jesus wants to start saving for college. His parents started an account for him that currently holds $325. Jesus adds $50 each m

erma4kov [3.2K]

Answer:

y-intercept, c = 325

Slope, m = 50

The x-axis represents the number of months and y-axis represents the total amount in saving accounts.

Step-by-step explanation:

We are given the following in the question:

A saving account currently holds $325. Jesus adds $50 each month.

Let x be the number of months and y be the total money n the saving account.

Then, we can use a linear function to represent the money in the account.

$y(x) = 325 + 50x$

Comparing to general linear function,

$y = mx + c$

where m is the slope and tells the rate of change and c is the y-intercept that is the value when x is zero.

Comparing we get:

m = 50

c = 325

y-intercept = c = 325

Slope, m = 50

The x-axis represents the number of months and y-axis represents the total amount in saving accounts.

The attached image shows a graph for the same.

7 0

1 year ago

People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the

Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

6 0

2 years ago