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Masteriza [31]
2 years ago
14

∠A and ∠C are right angles. m∠p = degrees.

Mathematics
2 answers:
almond37 [142]2 years ago
6 0
M<P 59° is your answer
Maru [420]2 years ago
5 0

Answer:

The measure of ∠p is 59.14°

Step-by-step explanation:

Given the figure in which ∠A and ∠C are right angles.

The length of AD=6 units , AB=5 units, CD=4 units

we have to find the measure of ∠p

In ΔBAD by Pythagoras theorem,

BD^2=AB^2+AD^

BD^2=5^2+6^2=25+36=61

BD=7.81024..\sim 7.8

Now, In Δ DCB

\cosp=\frac{CD}{BD}=\frac{4}{7.8}=0.513

p=\cos^{-1}0.513=59.14^{\circ}

The measure of ∠p is 59.14°

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The graph of f(x) = StartRoot x EndRoot is reflected over the y-axis. Use the graphing calculator to graph this reflection. Whic
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Answer:

<em>(–81, 9), (–36, 6), (–1, 1) </em> are the correct three points.

Step-by-step explanation:

Given the function:

f(x) =\sqrt x

Please refer to the attached image.

The green line shows the graph of actual function.

It is reflected over y axis.

The reflected graph is shown in black color in attached image.

When reflected over y axis, the sign of variable x changes from Positive to Negative.

So, the resultant function becomes:

f(x)=\sqrt{-x}

i.e. we will have to give the values of x as negative now.

so, the options in which value of x is negative are the possible answers only.

The possible answers are:

(–81, 9), (–36, 6), (–1, 1) and

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In the 2nd option, (–18, 9) does not satisfy the condition.

So, the correct answer is:

<em>(–81, 9), (–36, 6), (–1, 1)</em>

7 0
2 years ago
An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color
alekssr [168]

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36

Thus, the probability that only white balls are drawn is 0.36.

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Why are you allowed to move the decimal points before dividing with decimals? Explain your reasoning. I will give the brainliest
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Answer:

so you can make both your dividend and your divisor equal so you can divide

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2 years ago
There were 8 judges at a gymnastics competition. Kathleen received these scores for her performance on the uneven parallel bars.
Korolek [52]

Answer:

below

Step-by-step explanation:

mean : 8.8

The mean is the average, so you find it by adding all the numbers together and dividing by n, or how many numbers there are. For this, I added to get 70.4 and divided that by 8 (8 total scores).

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The middle numbers are 8.8 and 8.9, so you add those together and divide by 2 to get 8.85.  

mode : 8.9

The mode is just what number appears most often. Because 8.9 appears three times in this data set, more than any other number, the mode is 8.9.

b. The mean reflects a typical score because it is the average, and is used most often when someone is expressing a typical or "average" score. It is the score most people are likely to get, and as there are no outliers in this data set, it reflects a typical score for this data set. It is also the same as the mode, or most often score, in this data set.

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2 years ago
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