Of 100 diners in a restaurant, 45 ordered the fish of the day and 14 are wearing a dress. Of the diners who ordered fish, 8 are
2 answers:
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Answer:
Option A and Option B are not equivalent to the given expression.
Step-by-step explanation:
We are given the following expression:
Applying properties of exponents and base:
A. Using the exponential property , we can write:
which is not equal to the given expression.
B. Using the exponential property , we can write:
which is not equal to the given expression.
C. First we convert the radical form into exponent form. Then by using the property of exponent, we can write the following:
which is equal to the given expression.
D. First we convert the radical form into exponent form. Then by using the property of exponent, we can write the following:
which is equal to the given expression.
Option D and Option C are equivalent to the given expression.
Given:
A quadratic function has a line of symmetry at x = –3.5 and a zero at –9.
To find:
The other zero.
Solution:
We know that, the line of symmetry divides the graph of quadratic function in two congruent parts. So, both zeroes are equidistant from the line of symmetry.
It means, line of symmetry passes through the mid point of both zeroes.
Let the other zero be x.
Multiply both sides by 2.
Add 9 on both sides.
Therefore, the other zero of the quadratic function is 2.
Answer:
Therefore the value of k = 6.
Step-by-step explanation:
Given:
LN = m
NM = l
OM = k
NO = 4
LO = 8
LM = 8 + k and
Δ LNM ,Δ LON and Δ MON are right Triangle.
To Find :
Om = k = ?
Solution:
In Right angle Triangle By Pythagoras Theorem we have,
So, In Right angle Triangle Δ LON we have,
LN² = ON² + OL²
m² = 4² + 8²
m² = 80 ............( 1 )
Now in Right angle Triangle Δ MON we have,
MN² = ON² + MO²
l² = 4² + k² ....................( 2 )
Now In Right angle Triangle Δ LNM we have,
LM² = LN² + MN²
(8 + k)² = m² + l² .................( 3 )
Substituting equation 1 and equation 2 in equation 3
(8+k)² = 80 + 4² + k²
Applying (A+B)² = A² +2AB + B² we get
Therefore the value of k = 6.
