I think the points given here are plotted linearly:
FGHI. in this case, we can tell that FG + GH + HI = FI. substituting to the expression devised, 2 units + GH + 1 unit = 7 units. This is equal to 3 units + GH = 7 units. GH is then equal to 4 units.
So by definition, area is equal to the length (x) times the width (y). The area of the square mat is = x × y, or xy
If the area of<span> the rectangular mat is twice that of the square mat, the area of the rectangular mat would have to be = 2 </span>× x × y<span>
This can be written as 2x </span>× y, making the length of the rectangular mat twice that of the square mat's length, and the width the same as the square mat's width.<span>
</span>
<u>Given</u>:
Given that the regular decagon has sides that are 8 cm long.
We need to determine the area of the regular decagon.
<u>Area of the regular decagon:</u>
The area of the regular decagon can be determined using the formula,
where s is the length of the side and n is the number of sides.
Substituting s = 8 and n = 10, we get;
Simplifying, we get;
Rounding off to the nearest whole number, we get;
Thus, the area of the regular decagon is 642 cm²
Hence, Option B is the correct answer.
Denise is constructing A square.
Note: A square has all sides equal.
We already given two vertices M and N of the square.
And another edge of the square is made by from N.
Because a square has all sides of equal length, the side NO should also be equal to MN side of the square.
Therefore, <em>Denise need to place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass. That would make the NO equals MN.</em>
Therefore, correct option is :
D) place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass.
