A) The result of adding the two equations is
.. (2.5y +3x) +(5x -2.5y) = (27) +(5)
.. 8x = 32 . . . . . . . . . . . . . . . . . . . . . . . your 2nd selection
b) The solution to the system is (4, 6), your 4th selection.
.. This is the only choice with x=4, the solution to part (a).
the expected value for the 3 point shot = (3 * 0.30) + (0 * 0.70) = 0.90
the expected value for the 2 point shot = (2 * 0.48) + (0 * 0.52) = 0.96
the expected value for the 2 point shot is higher than the 3 point shot so he should pass the ball
Answer:
- The total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.
- The total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.
Step-by-step explanation:
a) How much will you have at the middle of the first year?
Using the formula
where
Given:
Principle P = $300
Annual rate r = 6% = 0.06 per year
Compound n = Semi-Annually = 2
Time (t in years) = 0.5 years
To determine:
Total amount = A = ?
Using the formula
substituting the values
$
Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.
Part b) How much at the end of one year?
Using the formula
where
Given:
Principle P = $300
Annual rate r = 6% = 0.06 per year
Compound n = Semi-Annually = 2
Time (t in years) = 1 years
To determine:
Total amount = A = ?
so using the formula
so substituting the values
$
Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.
Answer:
the last option: 
Step-by-step explanation:
Make sure you have the numerical answer for each of the functional expressions that are shown among the possible solution choices:
f(4) = -14 (what the blue function reads [its y-value] when x is 4)
g(4) = 10 (what the red function reads [its y-value] for x=4)
g(-2) = 4 (y-value of the red function when x is -2)
f(2) = -8 (y-value of the blue function for x = 2)
f(-2) = 4 (y-value of the blue function for x =-2)
use them to compare the options they give you, and the only one that matches is the last option.
