A plumber charges a $45 fee to make a house call and then $25 for each hour of labor. The plumber uses an equation in the form e
2 answers:
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Answer:
En 5 horas se habrá enterado todo el pueblo.
Step-by-step explanation:
Sabemos que en un pueblo 5 personas escucharon una noticia.
Una hora más tarde, cada una de ellas le contó la noticia a otras 5.
Luego, éstas contaron la noticia a otras 5 y así sucesivamente.
Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.
La ecuación a desarrollar para resolver el problema es la siguiente :
Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.
Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :
(I)
Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :
(II)
Buscamos el valor de que satisface la ecuación (II).
Probando y realizando las sumas encontramos que :
El valor de que satisface (II) es
.
Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.
Entonces para nuestro , el número de horas que pasaron son 5 horas (1 menos que el valor de
)
Todo el pueblo se habrá enterado en 5 horas de la noticia.
Answer:
The probability that the yellow M&M came from the 1994 bag is 0.07407 or 7.407%
Step-by-step explanation:
Given
Before 1995
(Br) Brown = 30%
(Y) Yellow = 20% =0.2
(R) Red = 20%
(G) Green =10% =0.1
(O) Orange = 10%
(T) Tan = 10%
After 1995
(Br) Brown = 13%
(Y) Yellow = 14% =0.14
(R) Red = 13%
(G) Green = 20% = 0.2
(O) Orange = 16%
(Bl) Blue = 24%
Since there are two bags, let A be the bag from 1994, and B be the bag from 1996
Then let AY imply we drew a yellow M&M from the 1994 bag
AG implies we drew a green M&M from the 1994 bag
BY implies imply we drew a yellow M&M from the 1996 bag
BG implies we drew a green M&M from the 1996 bag
P(AY) =0.2
P (BY) = 0.14
P(AG) =0.1
P(BG) =0.2
Since the draws from the 1994 and 1996 bag are independent,
therefore
The draws can happen in either of the 2 ways in (1) and (2) above
therefore total probability E is given as
E =
For the yellow one to be from 1994, it implies that the event to be chosen is
Since the total probability is given as E=0.054
then
Concluding statement: This is the condition for the Yellow one to come from 1994 and green from 1996 provided that they obey the condition from E
<h3><u><em>Question:</em></u></h3>
On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.
<h3><em><u>Answer:</u></em></h3>The variables are defined as:
"c" represent the number of cakes sold and "p" represent the number of pies sold
The system of equations used are:
c + p = 40 and 8c + 10p = 356
18 pies and 22 cakes were sold
<h3><em><u>Solution:</u></em></h3>Let "c" represent the number of cakes sold
Let "p" represent the number of pies sold
Cost of 1 pie = $ 10
Cost of 1 cake = $ 8
Given that total of 40 items were sold
number of cakes + number of pies = 40
c + p = 40 ------ eqn 1
<u><em>Given items were sold for $356</em></u>
number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356
8c + 10p = 356 ----- eqn 2
<u><em>Let us solve eqn 1 and eqn 2</em></u>
From eqn 1,
p = 40 - c ---- eqn 3
Substitute eqn 3 in eqn 2
8c + 10(40 - c) = 356
8c + 400 - 10c = 356
-2c = - 44
c = 22
<em>Substitute c = 22 in eqn 3</em>
p = 40 - c
p = 40 - 22
p = 18
Thus 18 pies and 22 cakes were sold