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Ad libitum [116K]
1 year ago
12

Evaluate the step function for the given input values. g(x) = StartLayout enlarged left-brace 1st row 1st column negative 4, 2nd

column negative 3 less-than-or-equal-to x less-than negative 1 2nd row 1st column negative 1, 2nd column negative 1 less-than-or-equal-to x less-than 2 3rd row 1st column 3, 2nd column 2 less-than-or-equal-to x less-than 4 4th row 1st column 5, 2nd column x greater-than-or-equal-to 4 EndLayout
g(2) =
g(–2) =
g(5) =
Mathematics
2 answers:
Ostrovityanka [42]1 year ago
5 0

Answer:

g(2) = 3

g(–2) = -4

g(5) = 5

Step-by-step explanation:

Sati [7]1 year ago
5 0

Answer:

no the graph c

Step-by-step explanation:

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It takes Daphne 25 minutes to assemble a model plane. During her work day Daphne takes 30 minutes for lunch and one 15 minute br
natka813 [3]

Answer:

<h2>y=25p-45</h2>

Step-by-step explanation:

We first of all start by cumulating all the time she spent for break

lunch= 30min

break= 15min

total break= 45min

also the time taken to assemble one model plane 25min

let the number of hours be p

and the total number of model plane be y

The model is

y=25p-45

7 0
2 years ago
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

4 0
1 year ago
The standard form of the equation of a parabola is x = y2 + 10y + 22. What is the vertex form of the equation?
iVinArrow [24]

From the conics form of the equation, shown above, I look at what's multiplied on the unsquaredpart and see that 4p = 4, so p = 1. Then the focus is one unit above the vertex, at (0, 1), and the directrix is the horizontal line y = –1, one unit below the vertex.

vertex: (0, 0); focus: (0, 1); axis of symmetry: x = 0; directrix: y = –1

Graph y2 + 10y + x + 25 = 0, and state the vertex, focus, axis of symmetry, and directrix.

Since the y is squared in this equation, rather than the x, then this is a "sideways" parabola. To graph, I'll do my T-chart backwards, picking y-values first and then finding the corresponding x-values for x = –y2 – 10y – 25:

To convert the equation into conics form and find the exact vertex, etc, I'll need to convert the equation to perfect-square form. In this case, the squared side is already a perfect square, so:

y2 + 10y + 25 = –x 
(y + 5)2 = –1(x – 0)

This tells me that 4p = –1, so p = –1/4. Since the parabola opens to the left, then the focus is 1/4 units to the left of the vertex. I can see from the equation above that the vertex is at (h, k) = (0, –5), so then the focus must be at (–1/4, –5). The parabola is sideways, so the axis of symmetry is, too. The directrix, being perpendicular to the axis of symmetry, is then vertical, and is 1/4 units to the right of the vertex. Putting this all together, I get:

vertex: (0, –5); focus: (–1/4, –5); axis of symmetry: y = –5; directrix: x = 1/4

Find the vertex and focus of y2 + 6y + 12x – 15 = 0

The y part is squared, so this is a sideways parabola. I'll get the y stuff by itself on one side of the equation, and then complete the square to convert this to conics form.

y2 + 6y – 15 = –12x 
y2 + 6y + 9 – 15 = –12x + 9 
(y + 3)2 – 15 = –12x + 9 
(y + 3)2 = –12x + 9 + 15 = –12x + 24 
(y + 3)2 = –12(x – 2) 
(y – (–3))2 = 4(–3)(x – 2)

Then the vertex is at (h, k) = (2, –3) and the value of p is –3. Since y is squared and p is negative, then this is a sideways parabola that opens to the left. This puts the focus 3 units to the left of the vertex.

vertex: (2, –3); focus: (–1, –3)

6 0
1 year ago
On a coordinate plane, a line is drawn from point A to point B. Point A is at (negative 8, negative 13) and point B is at (4, 11
juin [17]
10226321 because of the minus of the (1,5) 102374711
9 0
2 years ago
Read 2 more answers
Solve for x 3x−91&gt;−87 OR 21x−17&gt;25
klasskru [66]

Answer:

  x > 4/3

Step-by-step explanation:

The first inequality can be solved this way ...

  3x -91 > -87

  3x > 4 . . . . . . . add 91

  x > 4/3 . . . . . . divide by 3

__

The second inequality has solution ...

  21x -17 > 25

  21x > 42 . . . . . . add 17

  x > 2 . . . . . . . . . divide by 21

__

The solution set is the union of these overlapping solutions, so will be equal to the first solution:

  x > 4/3

5 0
2 years ago
Read 2 more answers
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