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1 year ago

Neptune is 2,798,842,000 miles from the sun. How many hours does it take lightto travel from the sun to Neptune?

Mathematics

1 answer:

Mrrafil [7]1 year ago

4 0

9514 1404 393

Answer:

4.17 hours

Step-by-step explanation:

The speed of light is about 670,616,629.4 miles per hour, so the travel time to Neptune is ...

(2,798,842,000 mi)/(670,616,629.4 mi/h) ≈ 4.17 h

It takes about 4.17 hours for light to travel from the sun to Neptune.

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Sam and Bruno were computing how many kilometers they rode in the 3 bike trips they took last month. In order, they rode 45.7, 4

TiliK225 [7]

Answer:

Correct solution:

45.7 + 40.9 + 38.0 = 124.6 miles. 124.6 divided by 0.621 = 200.64

Step-by-step explanation:

they rode 45.7, 40.9, and 38 miles

= (45.7 + 40.9 + 38) miles

= 124.6 miles

Convert 124 .6 miles to kilometers

1 kilometer = 0.621 miles

124.60 miles = 124.60 / 0.621

= 200.64 kilometers

This is the correct solution because he divided 124.60 miles by 0.621

45.7 + 40.9 + 38.0 = 124.6 miles. 124.6 divided by 0.621 = 200.64

4 0

1 year ago

Read 2 more answers

What can be concluded about the graphed polygon? mc013-1.jpg The polygon is a rectangle. Adjacent sides of the polygon are perpe

Usimov [2.4K]

From the given graph, the image is a trapezoid.
Therefore,
The first option, "the polygon is a rectangle" is incorrect.
The second option "Adjacent sides of the polygon are perpendicular." cannot be true as well because trapezoid has one the adjacent sides which is not perpendicular.
Third option" Opposite sides of the polygon are parallel", this can't be true as well because only two sides are parallel.
Fourth option " The slope of side c is 0.", this is true because line c is a horizontal line with zero rise and maximum run. Therefore,
Slope = 0 ÷ 9
 = 0

5 0

2 years ago

Read 2 more answers

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

1 year ago

After college graduation, Mario received employment offers from two companies. The first company offered a yearly salary of $31,

Alexandra [31]

The first thing we must do for this case is to define a variable:
x: number of years
y: total salary
We have then:
For first company:
y = 1500x + 31000
For second company:
y = 2000x + 28500
Equaling both equations we have:
1500x + 31000 = 2000x + 28500
Clearing x:
2000x - 1500x = 31000 - 28500
500x = 2500
x = 2500/500
x = 5
Answer:
It will take for the salaries to be the same about:
x = 5 years

3 0

1 year ago

What number must we multiply by $-\frac23$ to get a product of $\frac34$?

stich3 [128]

Let x be unknown number. If number x is multiplied by $-\dfrac{2}{3}$ and the product is equal to $\dfrac{3}{4},$ then