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ddd [48]
2 years ago
13

Consider the following sets. U = {all real number points on a number line} A = {solutions to the inequality 3x + 4 ≥ 13} B = {so

lutions to the inequality One-halfx + 3 ≤ 4} For which values of x is A ⋃ B = Ø? 2 3
Mathematics
1 answer:
blagie [28]2 years ago
7 0

Answer:

2 < x < 3

Step-by-step explanation:

Set A)

3x + 4 ≥ 13

3x ≥ 9

x ≥ 3

Set B)

0.5x + 3 ≤ 4

0.5x ≤ 1

x ≤ 2

Plot it out on a number line, and you'll see that 2 < x < 3

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In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence
expeople1 [14]

The question in part c is not clear, nevertheless, part a and part b would be solved.

Answer:

a. The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

b. The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

Step-by-step explanation:

a. Given

an + 2 = an + an + 1

where a1 = 1 and a2 = 1.

a3 = a1 + a2

= 2

a4 = a2 + a3

= 3

a5 = a3 + a4

= 5

a6 = a5 + a4

= 8

a7 = a6 + a5

= 13

a8 = a7 + a6

= 21

a9 = a8 + a7

= 34

a10 = a9 + a8

= 55

a11 = a10 + a9

= 89

a12 = a11 + a10

= 144

The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

(b)

Given

bn = an+1/an

b1 = a2/a1

= 1/1 = 1.000

b2 = a3/a2

= 2/1 = 1.000

b3 = a4/a3

= 3/2 = 1.500

b4 = a5/a4

= 5/3 = 1.667

b5 = a6/a5

= 8/5 = 1.600

b6 = a7/a6

= 13/8 = 1.625

b7 = a8/a7

= 21/13 = 1.615

b8 = a9/a8

= 34/21 = 1.619

b9 = a10/a9

= 55/34 = 1.618

b10 = a11/a10

= 89/55 = 1.618

The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

6 0
2 years ago
What is a27 of the sequence 15,10,5,…?
jeka57 [31]

-115

Using the arithmetic formula, your equation appears as so:

an = 15 + (27 - 1) - 5

15 being the first number in the sequence, 27 being the number you're trying to find, and -5 being the common difference.

This will give you the answer of -115.

Hope this helps!

8 0
2 years ago
Leena walked 2/3 of a mile What is 2/3 written as a sum of unit fractions with the denominator of nine
aliya0001 [1]
Bear in mind that multiplying anything, and anything whatsoever by 1, has a product of the anything itself.

so, let's multiply 2/3 by 1 then and check about,

\bf \cfrac{same}{same}=1\qquad thus\cfrac{2}{3}\cdot 1\implies \cfrac{2}{3}\cdot \cfrac{3}{3}\implies \cfrac{6}{9}&#10;\\\\\\&#10;\textit{now, we can split that and write it as a sum}\implies \cfrac{1+5}{9}\implies \cfrac{1}{9}+\cfrac{5}{9}
3 0
2 years ago
Let a and b be real numbers where a=/b=/c=/0 which of the following functions could represent the graph below?
Tresset [83]

Answer: The second option;  y =  (x - a)^2*(x-b)^4

Step-by-step explanation:

Ok, we have that a and b are real numbers different than zero.

In the graph, we can see that the line touches the x-axis in two values. Now, if we would have an equation like:

y = x*(x - a)^3*(x - b)^3

then when x = 0 we would have:

y = 0*(0-a)^3*(0-b)^3 = 0

But in the graph, we can see that when x = 0, the value of y is different than zero, so we can discard options 1 and 3.

So the remaining options are:

y = (x - a)^2*(x-b)^4

y = (x - a)^5*(x - b)

Now, another thing you can see in the graph is that it is always positive.

Particularly the second option allows negative values for y because it has odd powers, then we can also discard this option.

(For example, if x > a and x < b we would have a negative value for y)

Then the only remaining option is y =  (x - a)^2*(x-b)^4

3 0
2 years ago
A population that consists of 500 observations has a mean of 40 and a standard deviation of 15. A sample of size 100 is taken at
Alex17521 [72]

Answer:

<h3>The option D) 1.50 is correct</h3><h3>That is the standard error of the sample mean is 1.50</h3>

Step-by-step explanation:

Given that a population that consists of 500 observations has a mean of 40 and a standard deviation of 15.

A sample size is 100  taken at random from the given population.

<h3>To find the standard error of the sample mean :</h3>

From the given Mean=40 and \sigma =15

For N=100

<h3>The formula for standard error is SE_{mean}=\frac{\sigma}{\sqrt{N}}</h3>

Substitute the values in the above formula we get

SE_{mean}=\frac{15}{\sqrt{100}}

=\frac{15}{10}

=1.50

∴ SE_{mean}=1.50

<h3>∴ The standard error of the sample mean is 1.50</h3><h3>Hence the option D) 1.50 is correct</h3>
7 0
2 years ago
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