Time taken by Ria to paint a room = 4 hours
Time taken by Destiny to paint a room = 6 hours
If they work together, they complete 1 job. So,
The LCD of 4 and 6 is 12
Hence, both of them can paint the room in hours or 2.4 hours.
Consider the following sets. U = {all real number points on a number line} A = {solutions to the inequality 3x + 4 ≥ 13} B = {so
1 answer:
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Answer:
a)
b)
c)
And we can find the usual limits with:
And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.
d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.
And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.
Step-by-step explanation:
We have the following data:
11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2
Part a
We can calculate the sample mean with the following formula:
And if we replace we got:
For the median we need to sort the values on increasing order and we have:
8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8
Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:
The mode would be the most repeated value on this case:
Part b
The range is defined as and if we replace we got:
We can calculate the standard deviation with the following formula:
And if we replace we got:
Part c
For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.
We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and
And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got
Then we can find the IQR like this:
And we can find the usual limits with:
And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.
Part d
The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.
And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.
First off, we'll move the non-repeating part in the decimal to the left-side, by doing a division by a power of 10.
then we'll equate the value to some variable, and move the repeating part over to the left as well.
anyhow, the idea being, we can just use that variable, say "x" for the repeating bit, let's proceed,
and you can check that in your calculator.
then we'll equate the value to some variable, and move the repeating part over to the left as well.
anyhow, the idea being, we can just use that variable, say "x" for the repeating bit, let's proceed,
and you can check that in your calculator.
Check the picture below.
now, keep in mind that the focus point is at 3,0 and the directrix is to the left-hand-side of it, therefore, is a horizontal parabola, and it opens to the right-hand-side, like in the picture.
keep in mind that the vertex is half-way between the focus point and directrix, at a distance "p" from either one, notice the "p" distance is just 3 units, since the parabola is opening to the right, "p" is positive.
now, keep in mind that the focus point is at 3,0 and the directrix is to the left-hand-side of it, therefore, is a horizontal parabola, and it opens to the right-hand-side, like in the picture.
keep in mind that the vertex is half-way between the focus point and directrix, at a distance "p" from either one, notice the "p" distance is just 3 units, since the parabola is opening to the right, "p" is positive.