To solve this problem you must apply the proccedure shown below:
1. You have that the hyperbola <span>has a vertex at (0,36) and a focus at (0,39).
2. Therefore, the equation of the directrices is:
a=36
a^2=1296
c=39
y=a^2/c
3. When you susbtitute the values of a^2 and c into </span>y=a^2/c, you obtain:
<span>
</span>y=a^2/c
<span> y=1296/13
4. When you simplify:
y=432/13
Therefore, the answer is: </span><span>y = ±432/13</span>
Answer:
x > 36 in
Step-by-step explanation:
Let x = the width of the picture frame.
Then x + 6 = the length of the frame.
The formula for the perimeter P of a rectangle is'
P = 2l + 2w.
So, the condition is
2l + 2w > 156
2(x + 6) + 2x > 156 Distribute the 2
2x + 12 + 2x > 156 Combine like terms
4x + 12 > 156 Subtract 12 from each side
4x > 144 Divide each side by 4
x > 36
The perimeter of the picture frame will be greater than 156 in if x > 36 in.