It is hard to say how Faelyn's work shows the polynomial is prime, but it is.
There are no factors of 6*4 = 24 that add to -5, so the polynomial cannot be factored using real numbers.
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The expression of suggestion 2 is a different polynomial than the one Faelyn is factoring.
Taking a factor of 2x out of the first group does not help it match the factoring of the second group.
Dividing one or the other of the groups by -1 will not make the binomials the same.
You do the implcit differentation, then solve for y' and check where this is defined.
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0
Solve for y': y'(x²-2xy) +2xy - y² = 0
y' = (2xy-y²) / (x²-2xy)
Check where defined: y' is not defined if the denominator becomes zero, i.e.
x² - 2xy = 0 x(x - 2y) = 0
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y:
0^2*y - 0*y^2 =? 4 0 =? 4
This is impossible, hence the function is not defined for 0, and we can disregard this.
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16)
This is a possible value for y, so we have a point where y is defined, but not y'.
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-).
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...).
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function).
Answer:
Step-by-step explanation:
n + q = 20
.05n + .25q = 3.00
5n + 25q = 300
n + q = 20
5n + 25q = 300
-5n - 5q = -100
20q = 200
q = 10 quarters
n + 10 = 20
n = 10 nickels
(10 nickels, 10 quarters)
For this question, you need to understand how to divide fractions.First we line up our fractions appropriately:
4/9 ÷ 4/5 = ? (You want to divide 4/9 by 4/5)
4/9 × 5/4 = ? (Now we use the reciprocal of 4/5 and multiply instead of divide)
4 x 5 = 20 and 9 x 4 = 36. (Cross multiply.)
20/36 = 5/9. (Simplify to lowest terms.)
So, 4/9 divided by 4/5 is 5/9!But 5/9 is more than 4/9, so the answer is 0 :PCorrect me if I'm wrong.
Answer:
A: -2
Step-by-step explanation:
You want some factor k such that k(5x) +(10x) = 0. That is, 5k+10 = 0. The solution to this is k=-2, corresponding to selection A.
