I do not understand how to do this at all. Will someone please help me???
1 answer:
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<h3>Answer with explanation:</h3>
It is given that:
Circle 1 has center (−4, −7) and a radius of 12 cm.
Circle 2 has center (3, 4) and a radius of 15 cm.
Two circles are said to be similar if by some translation and dilation it could be placed over the other to form the same circle.
The circles are similar because the transformation rule ( x,y ) → (x+7,y+11) can be applied to Circle 1 and then dilate it using a scale factor of 5/4
( Since, as the center of circle 1 is (-4,-7)
so,
(-4+7,-7+11) → (3,4)
( Since, the radius of circle 1 is 12 and that of circle 2 is 15 cm.
so, let the scale factor be k .
that means :
)
Answer:
34°
Step-by-step explanation:
If m∠ADE is with 34° smaller than m∠CAB, then denote
m∠ADE=x°,
m∠CAB=(x+34)°.
Since DE ║ AB, then
m∠ADE=m∠DAB=x°.
AD is angle A bisector, then
m∠EAD=m∠DAB=x°.
Thus,
m∠CAB=m∠CAD+m∠DAB=(x+x)°=2x°.
On the other hand,
m∠CAB=(x+34)°,
then
2x°=(x+34)°,
m∠ADE=x°=34°.
