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1 year ago

9

a basketball player made 27 free throws in her last 45 tries. what is the experimental probability that she will make her next f

ree throw?

1 answer:

Strike441 [17]1 year ago

8 0

Hey mark me brainlest but ur answer is 27/45

Bess ur day.

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What percent of 55 is 34

mihalych1998 [28]

So,

To what percent 34 is of 55, we first need to find the fraction equivalent.

34 out of 55 parts or 34/55

Divide 34 by 55.

34/55 = 0.61818...

Now, we move the decimal point 2 places to the right in order to convert it to a percent.

6.1818...
61.81818...

Rounded to the nearest hundredth: 61.82%
Rounded to the nearest tenth: 61.8%
Rounded to the nearest percent: 62%

4 0

2 years ago

mark has a cabinet door in his kitchen with the dimensions shown below. he creates a scale drawing where the width of the cabine

laiz [17]

Answer:

$h^{*} = 25\,in$

Step-by-step explanation:

Let consider that door has a height of 5 feet and a width of 3 feet. The scale factor is:

$n = \frac{15\,in}{3\,ft}$

$n = 5\,\frac{in}{ft}$

The height of the cabinet is:

$h^{*} = n \cdot h_{door}$

$h_{*} = \left(5\,\frac{in}{ft} \right)\cdot (5\,ft)$

$h^{*} = 25\,in$

6 0

1 year ago

Read 2 more answers

Monica has a bag of marbles. There are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick

natima [27]

Answer:

$\frac{7}{64}\approx 0.11$

Step-by-step explanation:

We have been given that there are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick two marbles out of the bag replacing the first marble before picking the second marble.

Since Monica will replace the first marble before picking the second marble, therefore, probability of both events will be independent and probability of occurring one event will not affect the probability of second event's occurring.

Since the probability of two independent compound events is always the product of probabilities of both events.

$P(\text{A and B})=P(A)*P(B)$

Now let us find probability of picking a red marble out of 16 (4+7+5) marbles.

$P(Red)=\frac{\text{Total red marbles}}{\text{Total marbles}}$

$P(Red)=\frac{4}{16}$

Probability of picking blue ball out of 16 (4+7+5) marbles:

$P(Blue)=\frac{\text{Total blue marbles}}{\text{Total marbles}}$

$P(Blue)=\frac{7}{16}$

Now let us find probability of Monica picking a red and then a blue marble.

$P(\text{Red and Blue})=\frac{4}{16}\times \frac{7}{16}$

$P(\text{Red and Blue})=\frac{1}{4}\times \frac{7}{16}$

$P(\text{Red and Blue})=\frac{7}{4*16}$

$P(\text{Red and Blue})=\frac{7}{64}$

$P(\text{Red and Blue})=0.109375\approx 0.11$

Therefore, the probability of picking a red and then blue marble is $\frac{7}{64}\approx 0.11$ .

7 0

1 year ago

What is the answer to 3^=55

kakasveta [241]

I think it’s 1.7444921e+26

8 0

1 year ago

Simplify: –3(y + 2)2 – 5 + 6y What is the simplified product in standard form? y2 + y +

gayaneshka [121]

-3(y+2)2-5+6y
Steps
Multiply the numbers: 3 x 2 = 6
= -6(y + 2) - 5 + 6y
Then, expand - 6(y + 2): -6y - 12
= -6y - 12-5 + 6y
Simplify
-6y - 12 - 5 + 6y
= -17

3 0

1 year ago

Read 3 more answers