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NeTakaya
2 years ago
5

which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 2x – 1 into the quadratic formula below

? quadratic formula: x = -b±√b^2-4ac/2a
Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0

Answer:

Step-by-step explanation:

Its Option A for those who didn’t get the explanation.

irinina [24]2 years ago
5 0

0 = 4x^2+2x- 1

Quadratic formula is

x = \frac{-b+-\sqrt{b^2-4ac}}{2a}

'a' is the coefficient of x^2 = 4

'b' is the coefficient of x = 2

'c' is the constant = -1

Now we plug in all the values in quadratic formula

x = \frac{-b+-\sqrt{b^2-4ac}}{2a}

x = \frac{-2+-\sqrt{2^2-4(4)(-1)}}{2(4)}

x = \frac{-2+-\sqrt{18}}{8}

The above one is the substitution of values of a,b,c in quadratic formula.

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Adam lived a quarter of his life as a boy as fifth as a young man, a third in middle-age and 13 years in retirement. How old was
Anika [276]

ANSWER

Find out the how old was we when he died.

To proof

Let us assume that the age of the Adam be x

As given

Adam lived a quarter of his life as a boy as fifth as a young man, a third in middle-age and 13 years in retirement.

x =\frac{x}{4} +\frac{x}{5} +\frac{x}{3} + 13

L.C.M of denominator i.e ( 4,5,3) =60

than the equation becomes

60x = 15x + 12x +20x +780

60x - 47x = 780

13x = 780

x =\frac{780}{13}

x = 60 years

therefore the Adam age  when he died is 60 years.

Hence proved




5 0
2 years ago
A ball is launched into the sky at 19.6 feet per second from a 58.8 meter tall building. The equation for the ball's height. h,
Crazy boy [7]
H represents the height of the ball at a given time, symbolised as t.
Thus, we just need to find when h = 0 so that we find when it hits the ground.

0 = -4.9t² + 19.6t + 58.8
0 = 4.9t² - 19.6t - 58.8
0 = 49t² - 196t - 588
0 = t² - 4t - 12
0 = (t - 6)(t + 2)

So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.

Hence, at 6 seconds, the ball will strike the ground.
3 0
2 years ago
At a certain company, the annual winter party is always held on the second of Friday of December. What is the latest possible da
vitfil [10]

Answer:

The latest possible date is December, 14th.

Step-by-step explanation:

Notice that the second Friday of December is n+7, where n is the date for the first Friday of December. So, the latest the first Friday, the latest the second. As the weeks have seven days, the first Friday will be between 1st and 7th of each month. So, the latest first Friday will be 7th. Therefore, the latest second Friday will be 14th.

7 0
2 years ago
Dan invests £1200 into his bank account.
tresset_1 [31]

Answer:

300 euros

Step-by-step explanation:

1200 x 5 x 5=30000/100=300

6 0
2 years ago
Read 2 more answers
You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

3 0
2 years ago
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