Answer:
a) The probability that the life of the component is less than or equal to 6000 hours is 58%
b) The probability that the life is greater than 4000 hours is 96%
Step-by-step explanation:
Let's define the variable time as
, which is measured in hours. Then, according to the problem:
- The probability that the component survives for more than 6000 hours is 0.42

- The probability that the component survives no longer than 4000 hours is 0.04

a) The probability that the life of the component is less than or equal to 6000 needs to be equal to
.
To see this, think of a full set, whose elements can be separate in two categories, the ones that survive more than 6000 hours (let's call them A and number of elements of this type Na) and the ones that survive less than or equal to 6000 (let's call them B and number of elements of this type Nb). Thus, the total number of elements can be calculate as
, which represents the unit.
If you want to calculate the proportion of elements of type A, you need to divide the number of element of type A over the total number of elements, which is
. And the same analysis applies to the proportion of elements of type B:
. Hence, it is easy to see:

of course this only applies when the elements can be only categorized as one type or the other, which is call in probability, mutually exclusive events.
Using this for:
a) 
b) 
Answer:
The probability is
16%
Step-by-step explanation:
From the question we are told that
A is the event that the chip was "made by company A"
B is the event that a chip "survives 500 temperature cycles"
The probability that a computer chip survives more than 500 temperature cycles is
% 
The probability that does not survive more than 500 temperature cycles and it was manufactured by company A is 
The probability that the computer chip is not manufactured by company A and does not survive more than 500 temperature cycles is mathematically evaluated as

Where
are a A and B complements and | represented AND operator
So
![P(B' n A ' ) = [1 - P (B' | A )] [1 - P(B )]](https://tex.z-dn.net/?f=P%28B%27%20n%20A%20%27%20%29%20%3D%20%5B1%20-%20%20P%20%28B%27%20%7C%20A%20%29%5D%20%5B1%20-%20P%28B%20%29%5D)
substituting values
16%
Answer:
260,000
Step-by-step explanation:
The value decreases by 40,000 per year (500000-42000/2 years) the value will decrease by 240000 in six (4 years plus 2 years already passed) years. 6 x 40,000 =240000
So, the value should be 260,000 (500000-240000)
Or
year 1 500000-40000=460000
year 2 460000-40000=420000
year 3 420000-40000=380000
year 4 380000-40000=340000
year 5 340000-40000=300000
year 6 300000-40000=260000
Answer:
41
Step-by-step explanation:
add all numbers together then divide by how many numbers there are
<span>y=+- square root 5 over 3
y^2 + x^2 = 1 => x^2 = 1 - y^2 = 1 - 5/9 = 4/9 => x = +/- 2/3
Answer: x = +/- 2/3
y=+- square root 7 over 3
y^2 + x^2 = 1 => x^2 = 1 - y^2 = 1 - 7/9 = 2/9 => x = +/- (√2) / 3
Answer: x = +/-(√2)/3
y=+- 3 over 3
x^2 = 1 - y^2 = 1 - 3/9 = 1 - 1/3 = 2/3 => x = +/-(√2/3)
Answer: x = +/-√(2/3)
y=+- 2 square root 2 over 2
= y = +/- 2(√2) /2 = √2 ...... these y-coordinates are out of the unit circle, then there is not a corresponding x - coordinate for them.
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