A ball is launched into the sky at 19.6 feet per second from a 58.8 meter tall building. The equation for the ball's height. h,
at time t seconds is h=-4.9t^2+19.6t+58.8. When will the ball strike the ground
1 answer:
H represents the height of the ball at a given time, symbolised as t.
Thus, we just need to find when h = 0 so that we find when it hits the ground.
0 = -4.9t² + 19.6t + 58.8
0 = 4.9t² - 19.6t - 58.8
0 = 49t² - 196t - 588
0 = t² - 4t - 12
0 = (t - 6)(t + 2)
So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.
Hence, at 6 seconds, the ball will strike the ground.
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I'm not sure but I think it would be 10 pens hope this helps.
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The scale factor on a map is equal to
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Find how many miles are in the real life 
inches apart on the map
What ever number A is, it is going to be less than whatever number B is.
2.8y + 6 + 0.2y = 5y – 14
Simplify the left side:
3y +6 = 5y-14
Subtract 3y from both sides:
6 = 2y -14
Add 14 to each side:
2y =20
Divide both sides by 2:
y = 20 / 2
y = 10
