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ki77a [65]
2 years ago
14

A ball is launched into the sky at 19.6 feet per second from a 58.8 meter tall building. The equation for the ball's height. h,

at time t seconds is h=-4.9t^2+19.6t+58.8. When will the ball strike the ground
Mathematics
1 answer:
Crazy boy [7]2 years ago
3 0
H represents the height of the ball at a given time, symbolised as t.
Thus, we just need to find when h = 0 so that we find when it hits the ground.

0 = -4.9t² + 19.6t + 58.8
0 = 4.9t² - 19.6t - 58.8
0 = 49t² - 196t - 588
0 = t² - 4t - 12
0 = (t - 6)(t + 2)

So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.

Hence, at 6 seconds, the ball will strike the ground.
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Bob withdrew money from an ATM, put the receipt in an envelope, and filled in the information in his check register.
lora16 [44]

Answer:It is important to record each transaction so Bob knows how much money is in his account. That prevents being overdrawn. Recording debits and deposits helps with budgeting. It is good to keep receipts in case of any bank errors.

Step-by-step explanation:

5 0
1 year ago
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The 40th term of the number sequence is 119.<br> (b) Work out the 41st term of the number sequence.
dolphi86 [110]
100000fjwjsnfbc kdjdbf
7 0
1 year ago
A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at r
laila [671]

Answer:

Probability that Adam and Ella will be selected:

\displaystyle \frac{1}{10}=0.1

Step-by-step explanation:

Probabilities

The probability of a random event E to occur is a real number between 0 and 1, both inclusive, where 0 indicates an impossible event and 1 a sure event. There are many techniques to compute probabilities depending on the particular situation and distribution.

This question will be solved by simple calculations and logic, given its simplicity. We know the middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two of them are going to be selected at random to participate in the county chess tournament. We can calculate the number of different ways it can be done without any restriction. It's called the sample space.

The sample space of this event is the combination of 5 members regardless of their position. If {a,b,c,d,e} are the five members, then the possible combinations are {ab,ac,ad,ae,bc,bd,be,cd,ce,de}. Notice that there are only 10 possibilities because the combination ab is the same as ba since it's the same team for the tournament.

We can see there is only one combination of two specific letters out of 10. If a=Adam and e=Ella, only one combination is ae, the other 9 don't include both members, so the probability is

\displaystyle P(ae)=\frac{1}{10}=0.1

3 0
1 year ago
In how many ways can you spell the word ROOM in the grid below? You can start on any letter R, then on each step you can step on
Zina [86]

Answer:

  84? Not sure but pretty sure

Step-by-step explanation:

In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.

If 90° and reflex turns are allowed, then the number substantially increases.

Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.

2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.

Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.

Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.

6 0
1 year ago
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Crackers come in packages of 24. Cheese slices come in packages of 18. Andy wants one cheese slice for each cracker. Patrick mad
ANEK [815]

Patrick's statement is incorrect.

Explanation:

Crackers come in package of = 24

Cheese slices come in package of = 18

As given, Andy wants one cheese slice for each cracker so we will find the least common multiple of 24 and 18.

The L.C.M is 72.

So, Andy needs 72 crackers and 72 cheese slices.

Number of cracker packages needed=\frac{72}{24}=3

Number of cheese slice packages needed=\frac{72}{18}=4

Hence, Patrick's statement is incorrect. Andy needs 3 packages of crackers and 4 packages of cheese slices to make them even.










4 0
1 year ago
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