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pogonyaev
2 years ago
10

If the following fraction is reduced, what will be the exponent on the p? -5p^5q^4/ 8p^2q^2

Mathematics
2 answers:
viktelen [127]2 years ago
6 0
<span>-5p^5q^4/ 8p^2q^2
= -5p^3q^2

</span><span>exponent on the p will be 3

answer
</span><span>C.3</span>
oksano4ka [1.4K]2 years ago
6 0
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\&#10;a^{-{ n}} \implies \cfrac{1}{a^{ n}}&#10;\qquad \qquad&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}&#10;\qquad \qquad &#10;a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{-5p^5q^4}{8p^2q^2}\implies \cfrac{-5p^5q^4p^{-2}q^{-2}}{8}\implies \cfrac{-5p^5p^{-2}q^4q^{-2}}{8}&#10;\\\\\\&#10;\cfrac{-5p^{5-2}q^{4-2}}{8}\implies \cfrac{-5\boxed{p^3} q^2}{8}
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8 0
2 years ago
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A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form? A=–n2 + 3n + 5 B=n2 + 6n
slava [35]

Answer: B: n^2+6n+1

Step-by-step explanation:

A=n

B=2n+6

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AB-C

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4 0
2 years ago
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John deposited $2860 in a bank that pays 9% interest, compounded monthly. Find the amount he will have at the end of 3 years.
kati45 [8]
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2 years ago
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The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced
Dahasolnce [82]

Answer:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.86,0.13)  

Where \mu=5.86 and \sigma=0.13

We are interested on this probability

P(5.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

4 0
2 years ago
Cynthia rounds a number, x,to one decimal place. the result is 6.3.
gladu [14]

The answer is: 6.25\leq6.3

The explanation is shown below:

1. Cynthia rounds the number, which is identified as x, to one decimal place and the result is 6.3.

2. Based on this, we know that x could have been between 6.25 and 6.35. Therefore, the error interval for x is given by:

 6.25\leq6.3

Where \leq indicates that the value 6.25 is included and indicates that the value 6.35 is not included (Because if x had been exactly 6.35, Cynthia would round up to 6.4).

7 0
2 years ago
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