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Olegator [25]
1 year ago
15

Barbara draws pens randomly from a box containing 5 pens of the same shape and size. There is 1 green pen, 3 red pens, and 1 blu

e pen. She draws 1 red pen and then another red pen without replacing the first one. Find the probability of drawing 1 red pen followed by another red pen, and show the equation used.
Mathematics
1 answer:
Vinil7 [7]1 year ago
8 0
The contidion lets to establish that the events are independent.

Probability is the number of positive results / number of total events

The probability of drawing the first red pen is 3/5.

The probability of drawing the second red pen is 2/4

The combined propability is (3/5)*(2/4) = 6/20 = 3/10 = 0.30
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Answer:

(A)x + 3= x^2 + 2x-4

Step-by-step explanation:

Given the equations:

y = x + 3\\y= x^2 + 2x-4

Substitution simply means replacing the variable y in the second equation with its equivalent x+3 from the first equation.

Substitution of y into y=x^2 + 2x-4 gives us:

x + 3= x^2 + 2x-4

The correct option is A.

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2 years ago
Kiley can complete 35 math problems in 1 1/4 hours.How many can she complete in one hour
Lemur [1.5K]

Answer: 28


Step-by-step explanation:


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1 year ago
Read 2 more answers
On a coordinate plane, a cube root function goes through (negative 2.5, negative 3.5), crosses the y-axis at (0, negative 3), ha
mart [117]

Answer:

g(x) = \sqrt[3]{x-1} - 2

Step-by-step explanation:

We want to find h and k in:

g(x) = \sqrt[3]{x-h} + k

At the inflection point, the second derivative is equal to zero, so:

g'(x) = \frac{1}{3} (x-h)^{\frac{-2}{3}}

g''(x) = \frac{1}{3} \frac{-2}{3}(x-h)^{\frac{-5}{3}} = 0

Then x - h = 0.

Inflection point is located at (1, -2), replacing this x value we get:

1 - h = 0

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We know that the point (-2.5, -3.5) belongs to the function, so:

-3.5 = \sqrt[3]{-2.5-1} + k

k ≈ -2

All data, used or not, are shown in the picture attached.

4 0
2 years ago
A hospital finds that 22% of its accounts are at least 1 month in arrears. A random sample of 425 accounts was taken. What is th
GenaCL600 [577]

Answer:

8.85% probability that fewer than 82 accounts in the sample were at least 1 month in arrears

Step-by-step explanation:

For each account, there are only two possible outcomes. Either they are at least 1 month in arrears, or they are not. The probability of an account being at least 1 month in arrears is independent from other accounts. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.22, n = 425

So

\mu = E(X) = np = 425*0.22 = 93.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{425*0.22*0.78} = 8.54

What is the probability that fewer than 82 accounts in the sample were at least 1 month in arrears

This probability is the pvalue of Z when X = 82. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 93.5}{8.54}

Z = -1.35

Z = -1.35 has a pvalue of 0.0885.

8.85% probability that fewer than 82 accounts in the sample were at least 1 month in arrears

8 0
1 year ago
Jenny is eight years older then twice her cousin sues age. The sum of their ages is less then 32. What is the greatest age that
maw [93]

Answer:

The age of Sue could be 7 years

Step-by-step explanation:

Jenny is 8 years older than twice her cousin Sue's age.

The first equation will be :

J = 8 + 2S ---------(1)

The sum of their ages is less than 32.

The second equation will be :

J + S < 32  ----------------(2)

Now rearrange both equations :

8 + 2S + S < 32

3S < 32 - 8

3S < 24

S < 24/3

S < 8

S = 7

The age of Sue could be 7 years.

3 0
1 year ago
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