Substitute -3 for x in the expression
f(x)= 53 - 2x
f(-3)= 53 - 2(-3)
multiply -2 * -3
f(-3)= 53 + 6
add
f(-3)= 59
ANSWER: f(-3)= 59
Hope this helps! :)
Answer:
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
In step 6, David applied the distributive property.
Step-by-step explanation:
Given the polynomial :
80b⁴ – 32b²c³ + 48b⁴c
The Greatest Common Factor (GCF) of the coefficients:
80, 32, 48
Factors of :
80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80
32 : 1, 2, 4, 8, 16, and 32
48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.
GCF = 16
b⁴, b², b⁴
b⁴ = b * b * b * b
b² = b * b
b⁴ = b * b * b * b
GCF = b*b = b²
GCF of c³ and c
c³ = c * c * c
c = c
GCF = c
We can see that David's GCF of the coefficients are all correct
From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect
In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)
1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5