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docker41 [41]
2 years ago
14

Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data

sets shown are trueLogan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data sets shown are true?
City A

A box-and-whisker plot. The whiskers have a range of 10 and the box has a range of 3.

City B

A box-and-whisker plot. The whiskers have a range of 18.5 and the box has a range of 9.5.
City A is likely to have a colder temperatures because the interquartile range is smaller than that of City B.
City A is likely to have temperatures that remain fairly constant year round because it has a compact interquartile range compared to that of City B.
City A is likely to have very hot days and extreme temperatures because the mean is larger than that of City B.
City B is likely to have more warm days than City A because the maximum value is greater.
City B is likely to have more extreme temperatures with colder days in winter and hotter days in summer because the range is greater than that of A.
City B is likely to have more lower temperatures than City A because the median for City B is lower.
Mark this and return
Mathematics
2 answers:
Bad White [126]2 years ago
7 0

Answer:

The correct options are;

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A

Step-by-step explanation:

Here we have for City A

Maximum - Minimum = 10

Interquartile range =3

City B

Maximum - Minimum = 18.5

Interquartile range =9.5

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.

Y_Kistochka [10]2 years ago
7 0

Answer:a and d

Step-by-step explanation:

I took the test

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the probability that Jenya receives spam email is 4%.if she receives 520 email in a week about how much will be spam
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520*.04=20.8, or closer to 21 spam emails.
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2 years ago
1).He gastado 5/8 de mi dinero. Si en lugar de gastar los 5/8 hubiera gastado los 2/5 de mi dinero, tendria ahora 72 soles mas d
TiliK225 [7]

Answer:

1. The amount that was not spent is: 1080 soles

2. The answer is 5.

Step-by-step explanation:

Question 1. There are two situations:

If you spent 5/8 of the money then notice, that u did not spend 3/8.

If you spend 2/5 of the money, then you would have 72 more.

So think, this equation:

3/8x + 72 = 2/5x

2/5 of the money is the value for what you did not spend plus 72, the amount you would have, where x is the answer for the total of money.

72 = 2/5x - 3/8x

72 = 1/40x

x = 2880 soles

As you did not spend 3/8 of 2880, the answer is 1080 soles

Notice that if u spent 2/5 of 2880, you would have 1152 soles, so, the 1080 + 72, as the problem said.

Question 2.

We think letters for this excersise.

N = My born year

2020 (this year) - N = E (my age, now)

So N + 10 = when I get 10 years old

N + 20 = when I get 20 years old

N + 30 = when I get 30 years old

N + 40 = when I get 40 years old

The problem says:

(N+10) + (N+20) - (N+E) = 2020

((N+30)+E) - (N-40) = X  

So if 2020 - N = E, then notice that 2020 - E = N. Let's replace this in the equation form:

((2020-E)+10) + ((2020-E)+20) - ((2020-E)+E) = 2020

No minus in the first two terms, so we can break the ( )

2020-E+10 + 2020-E+20 - ((2020-E)+E) = 2020

We apply the distributive property for the second term

2020-E+10 + 2020-E+20 - 2020+E-E = 2020

We can cancel two E, and the 2020, so the new form will be:

2020 - 2E + 30 = 2020

We can also cancel the 2020, so if we reorder the equation, we have:

-2E = -30

E = 15 That's my age, so my born's year is 2020 - 15 = 2005 (N)

Look:

(2005 + 10) + (2005+20) - (2005+15) = 2020

So now, the last part

((2005+30)+15) - (2005+40) = 5

3 0
1 year ago
A dealer bought 3 gross buttons at $.38 a dozen. He sold the buttons at 5 cents each. How much was his profit per gross?(12 doze
777dan777 [17]

Answer:

$2.64

Step-by-step explanation:

Selling them at 5 cents each ($0.05), he could sell 1 dozen buttons for

12 * $0.05 = $0.60

As he bought them at $0.38 per dozen, the profit per dozen would be

$0.60 - $0.38 = $0.22

As 12 dozen is 1 gross, the profit per gross would be

12 * $0.22 = $2.64

7 0
2 years ago
Read 2 more answers
Consumer Reports scored cars on quality and cost. Spearman's rank correlation coefficient was calculated using Statdisk and the
melomori [17]

Answer:

d.There is insufficient evidence to conclude that the quality and price of a car are associated. There were ten cars used in the sample.

Step-by-step explanation:

Hello!

You have two variables X₁: quality score of a car and X₂: the price of a car.

It was analyzed id there is an association between the quality and the price.

The null hypothesis of a Spearman's rank correlation test is:

H₀: There is no association between the quality and the price of cars.

The researcher failed to reject the null hypothesis which means that there is no association between the variables of interest.

The sample size is listed in the output n= 10 consumer reports.

I hope you have a SUPER day!

8 0
2 years ago
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