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1 year ago

15

You want to rent a television. Company A charges 50$ per week plus a one time fee of 15$. Company B charges 30$ per week plus a

one time fee of 55$. After how many weeks are the total costs the same at both companies

1 answer:

SCORPION-xisa [38]1 year ago

4 0

Answer: 2 weeks

Step-by-step explanation:

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If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal

Vera_Pavlovna [14]

Answer:

y''=-1.26

Step-by-step explanation:

We are given that $2x^2+y^2=17$

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

$4x+2yy'=0$

$2x+yy'=0$

$yy'=-2x$

$y'=-\frac{2x}{y}$

Again differentiate w.r.t.x

Then , we get

$2+(y')^2+yy''=0$ $(u\cdot v)'=u'v+v'u)$

$2+(y')^2+yy''=0$

Using value of y'

$yy''=-2-(-\frac{2x}{y})^2$

$y''=-\frac{2+(-\frac{2x}{y})^2}{y}$

Substitute x=2 and y=3

Then, we get $y''=-\frac{2+(\frac{4}{3})^2}{3}$

$y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}$

Hence,y''=-1.26

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2 years ago

A study was conducted to determine the mean birth weight of a certain breed of kittens. Consider the birth weights of kittens to

kipiarov [429]

3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.

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1 year ago

Which is a true statement about the line x − 4y = 8?

Vedmedyk [2.9K]

The y-intercept of the line is (0, -2), the x-intercept is (8, 0). the slope of the line is in fact 1/4

so your answer is C.

hope this helps, God bless!

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2 years ago

Computer upgrades have a nominal time of 80 minutes. samples of five observations each have been taken, and the results are as l

Goshia [24]

The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is

for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin

in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0

the mean is x1 = (</span>79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
<span>its range is R 1= 81.0 -78.4 = 2.6

we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14 , R2=2.3
</span>S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4
<span>
therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0

we can say that the process is not in control.

</span>

3 0

2 years ago

An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i

xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0

1 year ago