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VLD [36.1K]
2 years ago
11

Three friends—Elaine, Kelly, and Shannon—all start for their college volleyball team. Each plays a different position: setter, m

iddle blocker, and outside hitter. Of the three, one is a freshman*, one a sophomore*, and the other a junior*.From the clues below, determine each woman's position and year in school.1. Elaine is not the setter.2. Kelly has been in school longer than the middle blocker.3. The middle blocker has been in school longer than the outside hitter.4. Either Kelly is the setter or Elaine is the middle blocker.
Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
6 0

Answer:

Elaine is the outside hitter in Freshman Year

Kelly is the setter in Junior Year

Shannon is the middle blocker in Sophomore Year

Please mark my answer as brainiest

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An animal shelter has $2500 in its reserve fund. The shelter charges $40 per animal placement and would like to have at least $4
Elena-2011 [213]

Answer:

Step 1

Write and solve the inequality:

2,500 + 40a ≥ 4,000, or 40a ≥ 1,500

a ≥ 37.5

Step 2

If the shelter places 30 cats and 10 dogs,

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2 years ago
The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (−1, 8). The ball reach
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Answer:

The required equation is:

y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4

Explanation:

Let us assume that the hole is at y = 0m, with x as the time.

From the question we have (-1s, 8m) as the vertex (here x being the time variable is supposed to be in seconds and y being the distance variable is supposed to be in meters)

At x = 1s, the ball gets to the hole, therefore we have point (1s, 0m)

We know that the vertex of the parabola y = ax² + bx + c is at

x =\frac{-b}{2a}

therefore we have:

-1 = \frac{-b}{2a}

We then have the following equations:

8 = a\times -1^2 + b\times -1 + c

0 = a\times -1^2 + b\times 1 + c

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From the 3rd equation we have

1 X 2a = b.

Therefore we have:

8 = a\times -1^2 - 1\times 2a\times1 + c

0 = a\times 1^2 + 1 \times2a\times 1 + c

We can simplify both equations and get:

8 = a\times( -1^2 - 2s^2) + c = -a\times 3^2 + c

0 = a\times(1^2 + 2^2) + c = a\times 3^2 + c

The first equation now becomes:

8 = -a\times 3 - a\times 3 = -a\times 6

a = frac{8}{-6} = -\frac{4}{3}

With a, we can find the values of c and b.

c = -a\times3 = -(-\frac{4}{3})*3 = 4

b = 1\times 2a = 1\times 2(-\frac{4}{3})= -\frac{8}{3}

Then the equation is:

y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4

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