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aivan3 [116]
2 years ago
6

Evaluate these quantities. a.−17 mod 2 b.144 mod 7 c.−101 mod 13 d.199 mod 19

Mathematics
1 answer:
Eduardwww [97]2 years ago
6 0
Modular arithmetic is used to find the remainder when dividing the first number by the second number you can divide the term then multiply the  (or use the mod function of a graphing calculator with the first term first in the ordered pair and the second in the second term.

-17/2 = 8.5   2*.5 =1
a. 1
-144/7 = -20 5/7 . 4/7 *7 = 4
b. 4
-101/13 =
c. 3
199/19=
d.9

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Which of the following is a key property of the quadratic parent function?
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Answer: B

Step-by-step explanation:

Quadratic parent function is y=x^2  which means the vertex is the origin because if you input 0 into the function you will get an output of zero. (0,0) is the origin which is where the graph intersect.

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Tony addison obtained a 20-year, $45,000 mortgage loan from united savings with an interest rate of 8.5%. his monthly payment is
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As given,  

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45000\times\frac{8.5}{100} = $3825  (this is yearly)

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2 years ago
10. If PQRS is a parallelogram, then P - R is:<br>(a) 20<br>(b) 30<br>(c) 90<br>(d) 0​
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The 154 tenth-graders at Wilson High School were polled on whether they enjoyed their algebra or geometry course more. The resul
kolbaska11 [484]

Answer:

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Two armadillos and three aardvarks sat in a five-seat row at the Animal Auditorium. What is the probability that the two animals
Serhud [2]

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Explanation:

The number of different ways in which the<em> two armadillos</em> would be at the ends of the row is 2:

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The number of different combinations in which<em> two of the three aardvarks </em>can sit at the ends of the row is P(3,2):

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Therefore, there are 2 + 6 = 8 different ways in which the two animlas on the ends of the row were both armadillos or both aardvarks.

Now calculate the total number of different ways in which the animals can sit. It is P(5,5):

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Thus, <em>the probability that the two animals on the ends of the row were both armadillos or both aardvarks</em> is equal to the number of favorable outputs divided by the total number of possible outputs:

      Probability=\dfrac{8}{120}=\dfrac{1}{15}

8 0
1 year ago
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