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GuDViN [60]
2 years ago
13

The maclaurin series expansion for sin(x) is: sin(x)=x−x33!+x55!−x77!+x99!−.... starting with simplest version sin(x)=x, add ter

ms one at time to estimate sin(π/8). after each new term is added, compute the true and approximate percent relative errors. add terms until value of approximate error estimation error falls bellow an error criterion conforming to two significant figures.

Mathematics
1 answer:
Simora [160]2 years ago
4 0
In the attached table, the true error (a) and the relative error (r) are multiplied by 100. The answer will be correct to 2 significant figures when these are below 0.5 and 1.3, respectively.

This occurs when the second term is added to the series.

_____
For reference, sin(π/8) = 0.382683432365...

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The length of a rectangular rug is 4 feet less than twice its width. The perimeter of the rug is 40 feet. Write a system of equa
Brrunno [24]

Answer:

Step-by-step explanation:

L=2W-4

40=2L+2W

The first equation uses the information that the length of a rectangular rug is 4 feet less than twice its width.

The second equation is using your standard perimeter equation of 2L+2W=perimeter of a rectangle.

Hope this is helpful :)

6 0
2 years ago
Adult panda weights are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds. The largest pandas
joja [24]

Answer:

16%

Step-by-step explanation:

THERE

4 0
2 years ago
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What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

5 0
2 years ago
Let $\overline{XY}$ be a tangent to a circle, and let $\overline{XBA}$ be a secant of the circle, as shown below. If $AX = 15$ a
KiRa [710]

Answer:

AB=5.4 units

Step-by-step explanation:

We using the theorem of intersecting tangent and secant to solve this.

By this theorem:

XY^2=XB \times AX\\9^2=15(15-XB)\\81=225-15XB\\15XB=144\\XB=9.6\\$Therefore:\\AB=AX-XB\\AB=15-9.6\\AB=5.4$ units

8 0
2 years ago
What is the 5th term of the geometric sequence a1=120, a2=36, a3=10.8, a6=0.2916
Serggg [28]
The fifth term of the geometric sequence would be 0.972
6 0
2 years ago
Read 2 more answers
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