Answer:
volume= length ×width×height
2×2.5×4.5
22.5
Answer:
The complete question in the graphic
A.
After synchronized exercise, it was observed that the average proximity rate has increased, which shows that the mean of the variable is positive and there is high synchronization in the groups.
.
B.
If groups with low synchronization and high effort are compared, the result of the average will be positive, so the average proximity rate will also increase after the synchronization exercise is performed.
On the contrary, if we observe the groups that have low synchronization and low effort, the mean of the variable is negative, thus the average proximity rate after performing the exercise will decrease.
(C)
considering that the total degrees of freedom is 259, it will show 260 students in the analysis.
D.
With a significance level of 5% or 0.05, the P value is less than the significance level, which leads to differentiating the mean of the scores before and after performing the combinations.
E.
With a significance level of 1% or 0.01, the p-value is higher than the significance level. With this data we can conclude that there is no difference between the results before and after the synchronized exercise
Answer: P(hist& french)=16/200=0.08
Step-by-step explanation:
To find the required probability we have to know what is the number of students that take both History and French ( Intersection of 2 circles in Venn diagram)
1. Lets find the number of students that take History or French or both.
We know that 8% from 200 take neither History or French. So number or students who take History or French or both is 200-200*0.08=184
2. Let number of students that takes French (or both Fr+Hist)=x (left circle)
So number of students that takes History (or both Fr+Hist)=4x (right circle)
So number of students that take both French+History= 10% from 4x or
0.1*4x=0.4x (circles' intersection)
3. Now we have the equation as follows:
x+4*x-0.4*x = 184
4.6*x=184
x=40 students takes French (or both French+ History)
4*x= 40*4=160 students takes History (or both French+ History)
10% from 160 =0.1*160=16 students takes both History and French
P(hist& french)=16/200=0.08
Answer:
P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)
Step-by-step explanation:
Here given that a basketball player that shoots 80% from the free throw line attempts two free throws.
If x is the no of shoots he makes (say) then we find that each throw is independent of the other.
In other words, because he made successful first attempt, his chances for second attempt will not change
Prob for success in each attempt remains the same as 0.80
Hence I throw is independent of II throw.
When A and B are independent,then we have
P(A/B) = P(A)
Hence answer is
P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)
