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eimsori [14]
2 years ago
9

the price of gravel is $24 for every 3/8 ton. Kate wants to know the price of 2 tons of gravel. at that rate, what is the price

of 2 tons of gravel
Mathematics
1 answer:
andreev551 [17]2 years ago
3 0

Answer:

<h2>$128</h2>

Step-by-step explanation:

This problem is on rate.

firstly we have to find the rate at which 1 ton is sold

given that 3/8 ton is sold for $24

hence 1 ton will be sold for X

cross multiply

X = 24/3/8

inverse the denominator and multiply the result with the numerator we have

X= 24*8/3

X= $64

Now having found out that 1 ton cost $64

2 tons will cost =64*2

                         = $128

Therefore at this rate two tons will cost $128

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A duck's mass at birth was 0.05 kilogram. The duck gained approximately 0.042 kilogram each week. After how many weeks is the du
Alex_Xolod [135]
Given that the first mass of the duck is 0.05 kg and it gains weight at a rate of 0.042 kg/week, the equation that would represent this scenario is,
                               y = 0.05 + 0.042x
where y is weight and x is the number of weeks. To determine the number of weeks in which the duck's mass becomes 0.890,   
                            0.890 = 0.05 + 0.042x
The value of x from the equation is 20. 
4 0
2 years ago
A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

<em />

<u>Sample 3</u>

Min= 50.25

Max= 53.12

Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

<em />

<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

8 0
2 years ago
A race car is driven by a professional driver at 99 . What is this speed in and ? 1 mile = 1.61 kilometers 1 hour = 60 minutes E
Lena [83]

Let us assume that the given speed is in miles per hour.

A race car is driven by a professional driver at 99 mph.

We have to find the speed in kilometer per hour and kilometer per minutes

As 1 mile = 1.61 km

So, 99 miles = 99\times1.61=159.39 kmph

1 km per hour = 0.0166 km per minute

So, 159.39 kmph = 159.39\times0.0166=2.6458 km per minute

Hence, The speed is equivalent to 159.39 kilometers /hour, or 2.645 kilometers/minutes .


7 0
2 years ago
Read 2 more answers
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
Arnold borrowed $7890 at 11.5 percent for five years. How much did Arnold pay in interest?
Rudiy27
937.5 is what I got.
5 0
2 years ago
Read 2 more answers
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