Rectangle B is shown below. Nadia drew a scaled version of Rectangle B using a scale factor of = and labeled

Mathematics

2 answers:

koban [17]2 years ago

6 0

Answer:

2 square units

Step-by-step explanation:

hello

The scale factor or linear scale factor is the ratio between the length of the same side in two similar figures.

in the graph we have a rectangle with width 5 units and long 10 units, and we know the scale factor is 1/5

$S_{f}=\frac{width(C)}{width(B)}\\ \\Width(B)*S_{f} =width(C)=5 units *\frac{1}{5} \\\\Width(C) =\frac{5}{5} units =1 unit$

$S_{f} =\frac{length (C)}{length(B)} \\\\\\length(C)=length(B)*S_{f}\\length(C)=(10*\frac{1}{5})$

$Length(C) =2 units\\\\ the area is A=w*l\\\\A=1 unit * 2 units\\\\\\$

A=2 square units

I hope it helps

Lina20 [59]2 years ago

4 0

Answer:

The area of rectangle C is 2

Step-by-step explanation:

Using a scale factor of $\frac{1}{5}$ yields the side lengths of 1 and 2

$(1)(2)=2$

You might be interested in

After four years of college, Erica has to start paying off all her student loans. Her first payment is due at the end of this mo

tatiyna

Answer:

Therefore, the approximate monthly payment is $548.85

Step-by-step explanation:

The amount of student loans Erica currently has = $34,006.00

The duration over which Erica is to pay back the loan = 7 years

The annual interest rate for the loan = 9.1%

Therefore, we have the geometric sequence formula is given as follows;

$A_n = P( 1 + r)^n - M \times \left [ \dfrac{(1 + r)^n-1}{r} \right ]$

Where;

M = The monthly payment

P = The initial loan balance = $34,006.00

r = The annual interest rate = 9.1%

n = The number of monthly payment = 7 × 12 = 84

Aₙ = The amount remaining= 0 at the end of the given time for payment

Substituting the values into the above formula, , we get;

$0 = 34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} - M \times \left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]$

$M = \dfrac{34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} }{\left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]} \approx 548.85$