Answer:
On a coordinate plane, a curve is level at y = -1 in quadrant 3 and then decreases rapidly into quadrant 4. It crosses the y-axis at (0, -2).
Step-by-step explanation:
y = -2 ^x -1
Given
Elysse paid for her sandwich and drink with a $10 bill and received $0.63 in change.
The sandwich cost $7.75 and sales tax was $0.47.
Find out the cost of her drink
To proof
Let the cost of her drink be x.
As given in the question
Elysse paid for her sandwich and drink with a $10 bill and received $0.63 in change.
Elysse paid for her sandwich and drink = 10 - 0.63
= $ 9.37
sandwich cost $7.75 and sales tax was $0.47
Than the equation becomes
x = 9.37 - (7.75 + 0.47)
x = 9.37 - 8.22
x = $ 1.15
The cost of the drink is $ 1.15.
Hence proved
For this case we have the following equation:
y = 3619000 (2.7) ^ 0.009t
We must evaluate the equation for the year 2000.
Therefore, we must replace the following value of t:
t = 2000 - 1994
t = 6
Substituting we have:
y = 3619000 (2.7) ^ (0.009 * 6)
y = 3818407.078
Round to the nearest ten thousand:
y = 3820000
Answer:
3820000 residents are living in that city in 2000
First of all, lets consider that you made a litte mistake and you meant this problem.........
<span>"The combined average weight of an okapi and a llama is 450 kilograms. The average weight of 3 llamas is 190 kilograms more than the average weight of one okapi. On average, how much does an okapi weigh, and how much does a llama weigh?"
This is a system of two equations.
Let it be X the average weight of a LLAMA
And Y the average weight of an OKAPI
X + Y = 450 kg 1)
3X = 190 kg +Y 2)
So, with 1) we have that Y = 450 - X
We subsitute in 2) and we have
3X = 190 + (450 -X).............We solve for X ....==> 4X = 640kg ==> X = 160kg
..We replace X in 1 and get => Y = 450kg -X = 450kg -160kg = 290kg
</span>160kg....... average weight of a LLAMA
290kg........average weight of an OKAPI