*Given
3(x+y)=y
y is not equal to zero
*Solution
1. The given equation is 3(x+y) = y and we are tasked to find the ratio between x and y. Distributing 3 to the terms in the parenthesis,
3(x+y) = y
3x + 3y = y
Transposing 3y to the right side OR subtracting 3y from both the left-hand side and the right-hand side of the equation would give
3x = -2y
Dividing both sides of the equation by 3,
x = (-2/3)y
Dividing both sides of the equation by y,
x/y = -2/3
Therefore, the ratio x/y has a value of -2/3 provided that y is not equal to zero.
Answer:
5.75x10^11
Step-by-step explanation:
quotient of 2,300 and (0.4x10^-8) is
2,300 ÷ (0.4x10^-8)
2300 = 2.3x10^3
We now have
2.3x10^3 / 0.4x10^-8
= (2.3/0.4) x ( 10^(3 - (-8))
= 5.75 x (10^(3+8))
= 5.75 x (10^11)
= 5.75x10^11
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The conversion rate US dollars to Euros is represented with the function:
E(n)=0.72n
n- number of dollars
E(n) - Euros as a function of US dollars
The conversion rate Euros to Dirhams is :
D(x)=5.10x
x- number of Euros
D(x)- Dirhams as a function of Euros
<span>We are trying to find D(x) in terms of n.
D(x) = 5.10x
x can be rewritten as E(n)
D(x) = 5.10(E(n))
D(x) = 5.10(E(n))
D(x) = 5.10(0.72n)
D(x) = 3.672n </span>
According to this the following statement is true:
A) <span>(D x E)(n) = 5.10(0.72n)</span>
Answer:
1. Take the Average of the distances the ball travelled each hit.
2. He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
3. He should use Mean
4. He should use Median. It best measures skewed data
Step-by-step explanation:
THE FIRST PART.
Raul should take the average of the distances the ball travelled each hit.
This is done by summing the total distances the ball travelled each bounce, and then dividing the resulting value by the total number of times he hit the ball, which is 10.
THE SECOND PART
He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
THE THIRD PART
He should take the mean of the distances of the ball that stayed infield.
This is the distance that occurred the most during the 9 bounces that stayed infield. The one that went outfield is makes it unfair to use any other measure of the center, taking the mean will give a value that is significantly below his efforts.
THE FOURTH PART
He should take the Median of the data, it is best for skewed data.
This is the middle value for all the distances he recorded.
Answer:
The correct option is (A) $304.47.
Step-by-step explanation:
The formula to compute the future value (<em>FV</em>) of an amount (A), compounded daily at an interest rate of <em>r</em>%, for a period of <em>n</em> years is:
![FV=A\times [1+\frac{r\%}{365}]^{n\times 365}](https://tex.z-dn.net/?f=FV%3DA%5Ctimes%20%5B1%2B%5Cfrac%7Br%5C%25%7D%7B365%7D%5D%5E%7Bn%5Ctimes%20365%7D)
The information provided is:
A = $300
r% = 1.48%
n = 1 year
Compute the future value as follows:
![=300\times [1+\frac{0.0148}{365}]^{365}\\\\=300\times (1.00004055)^{365}\\\\=300\times 1.014911\\\\=304.4733\\\\\approx \$304.47](https://tex.z-dn.net/?f=%3D300%5Ctimes%20%5B1%2B%5Cfrac%7B0.0148%7D%7B365%7D%5D%5E%7B365%7D%5C%5C%5C%5C%3D300%5Ctimes%20%281.00004055%29%5E%7B365%7D%5C%5C%5C%5C%3D300%5Ctimes%201.014911%5C%5C%5C%5C%3D304.4733%5C%5C%5C%5C%5Capprox%20%5C%24304.47)
Thus, the balance after 1 year is $304.47.
The correct option is (A).
