Given the conditional relative frequency table below which was generated by
column using frequency table data comparing the number of calories in a meal to
whether the meal was prepared at home or at a restaurant.
Number of Calories and Location of Meal Preparation.
Home Restaurant Total
≥ 500 calories 0.15 0.55 0.28
< 500 calories 0.85 0.45 0.72
Total 1.0 1.0 1.0
To determine whether there is an association between where food is prepared and the number of carories the food contain, we recall that an "association" exists between two categorical variables if the column conditional relative frequencies are different
for the columns of the table. The bigger the differences in
the conditional relative frequencies, the stronger the association
between the variables. If the conditional relative frequencies are
nearly equal for all categories, there may be no association between the
variables. Such variables are said to be <span>independent.
For the given conditional relative freduency, we can see that there is a significant difference between the columns of the table.
i.e. 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45
Therefore, we can conclude from the given answer options that t</span><span>here is an association because the value 0.15 is not similar to the value 0.55</span>
Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Answer:
84.80
Step-by-step explanation: 62.72+22.08=84.80
Question Completion:
How are the percentages distributed? Is the distribution skewed? Are there any gaps? (Select all that apply.)
Answer:
1. The percentages are concentrated from 20% to 60%.
2. These data are strongly skewed left.
3. There are no gaps in the data.
Step-by-step explanation:
1. Data
Percentage loss of wetlands per state
46 37 36 42 81 20 73 59 35 50
87 52 24 27 38 56 39 74 56 31
27 91 46 9 54 52 30 33 28 35
35 23 90 72 85 42 59 50 49
48 38 60 46 87 50 89 49 67
2. Re-arrangement of
Percentage loss of wetlands per state (in ascending order)
9 20 23 24 27 27 28 30
31 33 35 35 35 36 37 38
38 39 42 42 46 46 46 48
49 49 50 50 50 52 52 54
56 56 59 59 60 67 72 73
74 81 85 87 87 89 90 91
P(volleyball and baseball) = 4/200 x 100 = 2%
P(either volleyball or baseball) = P(volleyball ∪ baseball) = P(volleyball) + P(baseball) - P(volleyball and baseball) = 12% + 15% - 2% = 25%.
25% play either volleyball or baseball.
