Find the 12th term for the arithmetic sequence:

Match each set of vertices with the type of quadrilateral they form.

Serjik [45]

Only correct the first one.

Please, see the graph in the attached file.

1) a rectangle with    A(3,3), B(3,6),
noncongruent ←→ C(7,6), D(7,3)
adjacent sides
(in green)

2) a parallelogram
with A(2,0), B(3,2)
nonperpendicular ←→ C(6,3), D(5,1)
adjacent sides
(in blue)

3) a square ←→ A(3,3), B(2,5),
(in red) C(4,6), D(5,4)

4) a rhombus with       A(2,-2), B(3,0),
nonperpendicular    ←→ C(4,-2), D(3,-4)
adjacent sides
(in black)

5 0

2 years ago

Liam volunteers to help plan the event. The first month, he volunteered for x hours. The next month, he volunteered for 1 2/3 ti

Eddi Din [679]

Answer:

Hours in first month = 8

Step-by-step explanation:

AS it is given

He volunteered fr the first month = x hours

He volunteered for the second month = 12/3 times of first month

which will be = 12/3 * x

Total Hours volunteered = 40 hours

Now according to the given conditions

Volunteered first month + volunteered second month = total

putting this gives

x + 12/3 8 x = 40

as 12/3 = 4 so

it becomes

x + 4x = 40

solcing it will gives

5x = 40

x = 40/5

x = 8

So Numbers of hours worked in first month are 8

I hope this help you! :)

6 0

1 year ago

Five friends bake ginger bread and subsequently meet up for a tasting session. Each one gives one of his ginger

GenaCL600 [577]

Answer:

The five friends had 10 fingers to start with; one had two each

Step-by-step explanation:

The statement says each gave one of not all of his ginger in the toasting session.

4 0

2 years ago

A veterinarian does research on the causes of enteroliths, stones that develop in the colon of horses. She suspects that feeding

skad [1K]

Answer: 8

Step-by-step explanation:

The degree of freedom for t-distribution of testing the differnce between the two population mean is given by :-

$df= n_1+n_2-2$

, where $n_1$ = Size of first sample.

$n_1$ = Size of second sample.

As per given ,

Veterinarian selects five horses that are known to have enteroliths and compares the number of flakes of alfalfa they have eaten over a month with the number of flakes eaten by five horses free of enteroliths.

i.e. $n_1=5$ and $n_2=5$

Now , If she calculates a two-sample confidence interval by hand for the difference in the mean number of flakes fed to horses with and without enteroliths the degrees of freedom she should use are

$df= 5+5-2=8$

Hence, the correct answer is 8.

8 0

2 years ago

What is the liability to equity ratio of chester? select: 1 2.84 1.61 .31 4.35?

stiv31 [10]

Answer:

1.61

Step-by-step explanation:

The liability to equity ratio measures the gearing risk or leverage of the company. It is a financial ratio which is calculated by dividing total liabilities of a company by its shareholders equity. It measure the degree to which a company is financing its operations with debt.

8 0

2 years ago