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2 years ago

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Which applies the power of a power rule properly to simplify the expression (710)5? (710)5= 710 ÷ 5 = 72 (710)5= 710 - 5 = 75 (7

10)5= 710 + 5 = 715 (710)5= 710 · 5 = 750

1 answer:

Sever21 [200]2 years ago

7 0

We are asked in this problem to determine the condensed form of the expression (7^10)^5. we apply here the power rule in which exponents are multiplied to each other to get the expanded form. In this case, we multiply 10 by 5 that is a total of 50. hence the answer to this problem is D. 7^50

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The sampling distribution of certain statistical measures shows a normal distribution which of the following is an unbiased esti

svlad2 [7]

Answer:

A) Proportion.

Step-by-step explanation:

The distribution of sample proportions leads or may tends to approximate a normal distribution and is an unbiased estimator that has a graph that is usually distributed and is not skewed. In other words, simply, we can also say that the population proportion is basically defined to be as the mean of the sample proportion. The population proportion is basically equaled the expected value of the sample proportion.

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2 years ago

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Solve 3x + 2 = 15 for x using the change of base formula log base b of y equals log y over log b. −1.594 0.465 2.406 4.465

disa [49]

<u>Answer:</u>

The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

<u>Solution:</u>

Given, expression is $3^{(x+2)}=15$

We have to solve the above expression using change of base formula which is given as

$\log _{b} a=\frac{\log a}{\log b}$

Now, let us first apply logarithm for the given expression.

Then given expression turns into as, $x+2=\log _{3} 15$

By using change of base formula,

$x+2=\frac{\log _{10} 15}{\log _{10} 3}$

x + 2 = 2.4649

x = 2.4649 – 2 = 0.4649

Hence, the value of x is 0.465 approximately and second option is correct one.

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2 years ago

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Market-share-analysis company Net Applications monitors and reports on Internet browser usage. According to Net Applications, in

ASHA 777 [7]

Answer:

a) There is a 2.43% probability that exactly 8 of the 20 Internet browser users use Chrome as their Internet browser.

b) There is an 80.50% probability that at least 3 of the 20 Internet browsers users use Chrome as their Internet browser.

c) The expected number of Chrome users is 4.074.

d) The variance for the number of Chrome users is 3.2441.

The standard deviation for the number of Chrome users is 1.8011.

Step-by-step explanation:

For each Internet browser user, there are only two possible outcomes. Either they use Chrome, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

Google Chrome has a 20.37% share of the browser market. This means that $p = 0.2037$

20 Internet users are sampled, so $n = 20$ .

a.Compute the probability that exactly 8 of the 20 Internet browser users use Chrome as their Internet browser.

This is P(X = 8).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{20,8}.(0.2037)^{8}.(0.7963)^{12} = 0.0243$

There is a 2.43% probability that exactly 8 of the 20 Internet browser users use Chrome as their Internet browser.

b.Compute the probability that at least 3 of the 20 Internet browsers users use Chrome as their Internet browser.

Either there are less than 3 Chrome users, or there are three or more. The sum of the probabilities of these events is decimal 1. So:

$P(X < 3) + P(X \geq 3) = 1$

$P(X \geq 3) = 1 - P(X < 3)$

In which

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.2037)^{0}.(0.7963)^{20} = 0.0105$

$P(X = 1) = C_{20,1}.(0.2037)^{1}.(0.7963)^{19} = 0.0538$

$P(X = 2) = C_{20,2}.(0.2037)^{2}.(0.7963)^{18} = 0.1307$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0105 + 0.0538 + 0.1307 = 0.1950$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1950 = 0.8050$

There is an 80.50% probability that at least 3 of the 20 Internet browsers users use Chrome as their Internet browser.

c.For the sample of 20 Internet browser users, compute the expected number of Chrome users

We have that, for a binomial experiment:

$E(X) = np$

So

$E(X) = 20*0.2037 = 4.074$

The expected number of Chrome users is 4.074.

d.For the sample of 20 Internet browser users, compute the variance and standard deviation for the number of Chrome users.

We have that, for a binomial experiment, the variance is

$Var(X) = np(1-p)$

So

$Var(X) = 20*0.2037*(0.7963) = 3.2441$

The variance for the number of Chrome users is 3.2441.

The standard deviation is the square root of the variance. So

$\sqrt{Var(X)} = \sqrt{3.2441} = 1.8011$

The standard deviation for the number of Chrome users is 1.8011.

6 0

2 years ago

Subject On-Time Assignment Submission On-Time Arrival to Class Physics 89.7% 82.3% Math 88.2% 88.7% Chemistry 89.4% 83.1% Biolog

Alekssandra [29.7K]

Answer:

D. insufficient data

Step-by-step explanation:

We need to know the number of assignments in each class before we can tell the probability of interest.

__

If we assume the same number of assignments in each class, then 25.1% of on-time assignments were in physics. We note this is not an answer choice, further confirming we have <em>insufficient data</em>.

7 0

2 years ago

1) Mrs. Merson is selling her car. Her research shows that the car has a current value of $5,500,

SVEN [57.7K]

The right answer is Option B: $\frac{5500}{p}=\frac{55}{100}$

Step-by-step explanation:

Given,

Current value of car = $5500

This is 55% of the original value.

Let,

p be the original price of car.

Therefore,

55% of p = 5500

$\frac{55}{100}p=5500$

Dividing both sides by p

$\frac{55}{100}*\frac{p}{p}=\frac{5500}{p}\\\frac{55}{100}=\frac{5500}{p}$

The equation $\frac{5500}{p}=\frac{55}{100}$ can be used to find the price Mrs. Merson paid for the car.

The right answer is Option B: $\frac{5500}{p}=\frac{55}{100}$

Keywords: percentage, division

Learn more about percentages at:

#LearnwithBrainly

0 0

2 years ago