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2 years ago

What is the value of the 19th term in the sequence -1, -5, -9, ...?

2 answers:

8 0

-5 -(-1) = -5+1= -4
and
-9 -(-5) = -9+5 = -4

we observe that the number are in AP

of the AP -
ist term = -1
common difference = -4
19th term = -1 + (19-1)(-4)= -1 -72 = -73
_________________________

the correct answer = B

german2 years ago

3 0

The Arithmetic Sequence formula is:
an = a1 + (n-1)(d) where d is the common difference and a1 is the first term in the sequence.
a19 = -1 + (19 - 1)( -4)
a19 = -1 + (18 * -4)
a19 = -1 + (-72)
a19 = -73
LETTER B

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Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 5, the length of B C is 3, and the length

svetoff [14.1K]

The side opposite to angle B is the side that does not contact with angle B.

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Therefore, the lenght of the side opposite to angle B is 4 units.

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2 years ago

The list shows the area in square feet of each apartment available for rent in a building. 565, 961, 867, 517, 627, 714, 517, 72

gladu [14]

STEP 1:
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517, 517, 565, 627, 714, 728, 867, 961

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8 0

2 years ago

Read 2 more answers

There are 135 people in a sport centre. 73 people use the gym. 59 people use the swimming pool. 31 people use the track. 19 peop

Anna71 [15]

Answer:

1/9

Step-by-step explanation:

135 in Sport centre: Total

59:swimming pool

31:track

19 both swimming and gym

16 gym and track

4 all three facilities

4 people use all three facilities, then

16 - 4 = 12 people use the gym and the track and do not use the pool;

9 - 4 = 5 people use the pool and the track and do not use the gym;

19 - 4 = 15 people use the gym and the pool and do not use the track.

At least two facilities use 4 + 12 + 5 + 15 = 36 people, 4 of them use all three facilities. Thus, the probability that a randomly selected person which uses at least two facilities, uses all the facilities is

4/36=1/9

Hope this helps!!!

6 0

2 years ago

4C. Quintin is using the three different shaped

Sauron [17]

The smallest number of tiles Quintin will need in order to tile his floor is 20

The given parameters;

number of different shapes of tiles available = 3

number of each shape = 5

area of each square shape tiles, A = 2000 cm²

length of the floor, L = 10 m = 1000 cm

width of the floor, W = 6 m = 600 cm

To find:

the smallest number of tiles Quintin will need in order to tile his floor

Among the three different shapes available, total area of one is calculated as;

$A_{one \ square \ type} = 5 \times 2000 \ cm^2 = 10,000 \ cm^2$

Area of the floor is calculated as;

$A_{floor} = 1000 \ cm \times 600 \ cm = 600,000 \ cm^2$

The maximum number tiles needed (this will be possible if only one shape type is used)

$maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number= 60$

When all the three different shape types are used we can get the smallest number of tiles needed.

The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

$3 \times \ smallest \ number = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20$

Thus, the smallest number of tiles Quintin will need in order to tile his floor is 20

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3 0

2 years ago

the area of a trapezium is 594 sq. cm. The lengths of its parallel sides are in the ratio 4 : 5. The height of the trapezium is

Sophie [7]

Answer:

1st side=44 cm, 2nd side= 55cm

Step-by-step explanation:

let a = '4x' , b = '5x'

h= 12cm

Area of trapezium=1/2*(a+b)h

area=594=1/2*9x*12

594*2/12=9x

594/6=9x

99=9x

99/9=11=x

therefore, 4x=4*11=44cm

&5x=5*11=55cm

5 0

1 year ago