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2 years ago

Angela has the following coins in her pocket:

Mathematics

1 answer:

GaryK [48]2 years ago

7 0

Answer:

There are 10 different combinations

The list of different combinations is:

(10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

(1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

Explanation:

The possible combinations are:

1. Assuming the first coin is 10p:

(10p, 1p)
(10p, 50p)
(10p, 2p)
(10p, 20p)

2. Asuming the first coin is 1p

Do not count (1p, 10p) as it is the same combination as (10p, 1p)

(1p, 50p)
(1p, 2p)
(1p, 20p)

3. Assuming the first coin is 50p:

Do not count (50p, 10p) nor (50p, 1p) as they are the same combinations (10p, 50p) and (1p, 50p) counted earlier:

(50p, 2p)
(50p, 20p)

4. Assuming the first coin is 2p:

The only new combination is:

(2p, 20p)

5. All the combinations with 20p have already been listed.

Therefore:

There are 4 + 3 + 2 + 1 = 10 different combinations

The list of different combinations is:

(10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

(1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

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