<span>The answer is c. 1.5r + 2.5(5 – r) = 10.50. Let r be the number of raisins and p be the number of peanuts. Raisins cost $1.50 per pound: 1.5r. Peanuts cost $2.50 per pound: 2.5p. Jeremy spends $10.50: 1.50r + 2.50p = 10.50. Jeremy makes 5 pounds of trail mix: r + p = 5. So, we have the system of two equations: 1.5r + 2.5p = 10.50 and r + p = 5. Use the second equation to express p: p = 5 - r. Now, substitute p in the first equation: 1.5r + 2.5(5 - r) = 10.50. Therefore, the correct choice is c. 1.5r + 2.5(5 – r) = 10.50.</span>
Answer:
The no. of possible handshakes takes place are 45.
Step-by-step explanation:
Given : There are 10 people in the party .
To Find: Assuming all 10 people at the party each shake hands with every other person (but not themselves, obviously) exactly once, how many handshakes take place?
Solution:
We are given that there are 10 people in the party
No. of people involved in one handshake = 2
To find the no. of possible handshakes between 10 people we will use combination over here
Formula : 
n = 10
r= 2
Substitute the values in the formula
No. of possible handshakes are 45
Hence The no. of possible handshakes takes place are 45.
Answer:
0.94
Step-by-step explanation:
The question after this basically is:
<em>"If the applicant passes the "aptitude test for managers", what is the probability that the applicant will succeed in the management position?"</em>
<em />
So,
P(successful if hired) = 60% = 0.6 [let it be P(x)]
P(success at passing the test) = 85% = 0.85 [let it be P(y)]
P(successful and pass the test) = P(x) + P(y) -[P(x)*P(y)]
So,
P(successful and pass the test) = 0.6 + 0.85 - (0.6*0.85) = 0.94 (94%)
Place value is the value each digit has in its position: in order from higher to lower value, there is thousands, hundreds, tens, and ones.
When you divide by 10, you are moving (only once) every digit from its present place value to the right.
For example 6430 : 10= 643, you have moved every digit to the right, making the zero disappear (or better yet, separated by a hidden and in this case useless comma).
