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Vadim26 [7]
2 years ago
7

Which is a factor of 5x2 − 15x − 20?

Mathematics
1 answer:
Sholpan [36]2 years ago
7 0

Answer:

x= -1, x=4

Step-by-step explanation:

5x²-15x-20

5x²-20x+5x-20=0

5x(x-4) +5(x-4)

(5x+5) (x-4) =0

5x=-5 or x=4

x= -5/5. or x=4

x= -1 or x=4

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Mrs. Garcia borrowed some money at the rate of 4% per annum for the first year, at the rate of 6% pe r annum for the next 2 year
s2008m [1.1K]

Answer: ₱40,909.1

Step-by-step explanation:

Given data:

Rate for first year = 4%

Rate for next two years = 6%

Rate for the next 3 years = 7.5%

Interest paid back after 5years = ₱ 15,750

Solution:

How much did she borrow.

= let the sum borrowed be P

= P * 4 / 100

= 4P/100

= 1P/25.

For the next two years

= P* 6 * 2/100

= 12P/100

= 3P/25

For the next 3years

= P* 7.5*3/100

= 22.5P/100

= 9P/40.

1P/25 + 3P/25 + 9P/40 = 15750

77P/200 = 15750

P = 15750 * 200 / 77

P = 315,0000/77

P = ₱40,909.1

The amount borrowed is ₱40,909.1

5 0
2 years ago
Last year your professor wanted to study the pattern in class grades. The following table contains a sample of grades collected
Maslowich

Answer:

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

Step-by-step explanation:

<u>Mean:-</u>

The mean (average) is found by adding all of the numbers together and dividing by the number of items and it is denoted by x⁻

                                                                                                                           mean =  \frac{64+80+75+98+75}{5}

mean (x⁻ ) = 78.4

The mean of the given data = 78.4

<u>Median:</u>

The median is found by ordering the set from lowest to highest and finding the exact middle.

64 ,75, 80, 98

The middle term of the given data set = \frac{75+80}{2} =77.5

<u>Mode :</u>

The mode is the most common repeated number in a data set.

64 ,75, 75, 80, 98

in data the most common number = 75

<u>Conclusion</u>:-

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

   

8 0
2 years ago
Caroline knows the height and the required volume of a cone-shaped vase she’s designing. Which formula can she use to determine
timama [110]

Answer:

Option B. r=\sqrt{\frac{3V}{\pi h}}

Step-by-step explanation:

we know that

The volume of a cone is equal to

V=\frac{1}{3}\pi r^{2} h

Solve for the radius r

That means-----> isolate the variable r

Multiply by 3 both sides

3V=\pi r^{2} h

Divide by (\pi h) both sides

r^{2}=\frac{3V}{\pi h}

square root both sides

r=\sqrt{\frac{3V}{\pi h}}

4 0
2 years ago
A rectangular prism has a volume of 320 cubic cm. Its height is 8 cm. What is the area of its base? A 40 square cm B 4 square cm
Airida [17]
Volume of a prism is height x base x length. the area of the base would be calculated from the volume/ height so 
320/8 = 40 cm squared
3 0
2 years ago
Let’s assume the following statements are true: Historically, 75% of the five-star football recruits in the nation go to univers
marishachu [46]
<span>Given:
75% of the five-star football recruits in the nation go to universities in the three most competitive athletic conferences. </span>→ 25% goes to other schools.
<span>
five-star recruits get full football scholarships 93% of the time, regardless of which conference they go to. </span>→ 7% of the 5-star recruits don't get full football scholarships.<span>

a. The probability that a randomly selected five-star recruit who chooses one of the best three conferences will be offered a full football scholarship? 
75% * 93% = 69.75%

b. What are the odds a randomly selected five-star recruit will not select a university from one of the three best conferences?
25% of selected five-star recruit will not select a university from one of the three best conferences. I got the number based on the given data. Since, 75% will go, the remaining percent won't go. Total percentage should be 100% of the population. 

c. Explain whether these are independent or dependent events. Are they Inclusive or exclusive? 
These are independent events. One can still go to different school and still be legible for the full football scholarship. 

For question 2, pls. see attachment.</span>

4 0
2 years ago
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