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Vadim26 [7]
2 years ago
7

Which is a factor of 5x2 − 15x − 20?

Mathematics
1 answer:
Sholpan [36]2 years ago
7 0

Answer:

x= -1, x=4

Step-by-step explanation:

5x²-15x-20

5x²-20x+5x-20=0

5x(x-4) +5(x-4)

(5x+5) (x-4) =0

5x=-5 or x=4

x= -5/5. or x=4

x= -1 or x=4

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Answer:

Choice D - 8cm and 9cm.

Step-by-step explanation:

The other sides are not greater than 13.

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Sally needs 300 stickers. Vince gives her 12 packs with 10 stickers in each pack. How many stickers dose sally need now? Draw a
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F(x)=3x 2 +9f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 9 and g(x)=\dfrac{1}{3}x^2-9g(x)= 3 1 ​ x 2
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Answer:

f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252

g(f(x)) = 3x^4 + 18x^2 + 18

<em>f(x) and g(x) and not inverse functions</em>

Step-by-step explanation:

Given

f(x) = 3x^2 + 9

g(x) = \dfrac{1}{3}x^2 - 9

Required

Determine f(g(x))

Determine g(f(x))

Determine if both functions are inverse:

Calculating f(g(x))

f(x) = 3x^2 + 9

f(g(x)) = 3(\frac{1}{3}x^2 - 9)^2 + 9

f(g(x)) = 3(\frac{1}{3}x^2 - 9)(\frac{1}{3}x^2 - 9) + 9

Expand Brackets

f(g(x)) = (x^2 - 27)(\frac{1}{3}x^2 - 9) + 9

f(g(x)) = x^2(\frac{1}{3}x^2 - 9) - 27(\frac{1}{3}x^2 - 9) + 9

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f(g(x)) = \frac{1}{3}x^4 - 18x^2 + 252

Calculating g(f(x))

g(x) = \dfrac{1}{3}x^2 - 9

g(f(x)) = \frac{1}{3}(3x^2 + 9)^2 - 9

g(f(x)) = \frac{1}{3}(3x^2 + 9)(3x^2 + 9) - 9

g(f(x)) = (x^2 + 3)(3x^2 + 9) - 9

Expand Brackets

g(f(x)) = x^2(3x^2 + 9) + 3(3x^2 + 9) - 9

g(f(x)) = 3x^4 + 9x^2 + 9x^2 + 27 - 9

g(f(x)) = 3x^4 + 18x^2 + 18

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Represent f(x) with y

y = 3x^2 + 9

Swap positions of x and y

x = 3y^2 + 9

Subtract 9 from both sides

x - 9 = 3y^2 + 9 - 9

x - 9 = 3y^2

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Divide through by 3

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Take square root of both sides

\sqrt{y^2} = \sqrt{\frac{x}{3} - 3}

y = \sqrt{\frac{x}{3} - 3}

Represent y with g(x)

g(x) = \sqrt{\frac{x}{3} - 3}

Note that the resulting value of g(x) is not the same as g(x) = \dfrac{1}{3}x^2 - 9

<em>Hence, f(x) and g(x) and not inverse functions</em>

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