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2 years ago

Which is a factor of 5x2 − 15x − 20?

Mathematics

1 answer:

Sholpan [36]2 years ago

7 0

Answer:

x= -1, x=4

Step-by-step explanation:

5x²-15x-20

5x²-20x+5x-20=0

5x(x-4) +5(x-4)

(5x+5) (x-4) =0

5x=-5 or x=4

x= -5/5. or x=4

x= -1 or x=4

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Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of

nikklg [1K]

Answer:

a. 5 + 2i, 13 + 2i, 29 + 2i

Step-by-step explanation:

We'll use the formula f(z) = 2z + (3 - 2i) for each iteration. The output of the first iteration will be come the input of the second iteration, and so on.

So, we start with z0 = 1 + 2i and we plug that into the base equation:

z0 = 1 + 2i ==> f(z) = 2(1 + 2i) + 3 - 2i = 2 + 4i + 3 - 2i = 5 + 2i

z1 = 5 + 2i ==> f(z) = 2(5 + 2i) + 3 - 2i = 10 + 4i + 3 - 2i = 13 + 2i

z2 = 13 + 2i ==> f(z) = 2(13 + 2i) + 3 - 2i = 26 + 4i + 3 - 2i = 29 + 2i

z3 = 29 + 2i

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2 years ago

Read 2 more answers

there are 50 competitors in the mens ski jumping. 30 move on to the qualifying round. how many different ways can the qualifying

Andru [333]

They can take the 30 best abd remove the 20 worst, or remove the 20 best and send on the 39 worst.

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2 years ago

Annabelle measures the sides of 15 right triangles and, based on her observations, she concludes that for any right triangle the

saul85 [17]

Answer: Annabelle is using the a measure of central tendency defined as the Mode.

Step-by-step explanation: A measure of central tendency in its simplest definition is a single value or measure that can safely be used to represent all members belonging to an entire set of given data. Hence, as a good illustration, one figure can be used to confidently represent all other ninety nine figures where a set of one hundred figures were given.

The mean, median and mode are commonly accepted measures of central tendency.

The mode is the most frequently occurring value in a given set of data. As such, the modal value is statistically acceptable as a representative of the entire set of values or data.

If Annabelle measures the sides of 15 right triangles and based on her observations, she concludes that for any right triangle the sum of the squares of the two legs is equal to the square of the hypotenuse, what she has done is taking the most frequently occurring value, and in her experiment, the most frequent of all observed data satisfies the Pythagorean Theorem.

That is why Annabelle can confidently make her assumption.

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2 years ago

during the summer winnie delivers flowers and bob babysits for neighbors to show their earnings winnie makes a table which state

miv72 [106K]

Winnie earns $12.30 and Bob earns $24.30.
Bob earns $8.10 and earns$4.10
Winnie earns$12.15 and Bob earns $6.15
Winnie earns $4.05 and Bob earns $2.05

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2 years ago

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The mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of

grandymaker [24]

Answer:

At the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Step-by-step explanation:

We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.

The ship building association wishes to find out whether their welders earn more or less than $20,000 annually.

Let $\mu$ = mean gross annual incomes of certified welders

So, Null Hypothesis, $H_0$ : $\mu$ = $20,000

Alternate hypothesis, $H_A$ : $\mu \neq$ $20,000

Here, null hypothesis states that the mean income of welders is equal to $20,000.

On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.

Also, the test statistics that would be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean income

$\sigma$ = population standard deviation = $2,000

n = sample size

Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

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2 years ago