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german
1 year ago
5

Paula weighed 65.5 kilograms before she started training she as lost 3500grams how much does she weigh

Mathematics
2 answers:
castortr0y [4]1 year ago
6 0

1 kilogram = 100 grams

3500 / 1000 = 3.5 kilograms

65.5 - 3.5 = 62

she weighs 62 kilograms

Alborosie1 year ago
5 0
Hello!

We have the following data:

Paula weight (before training) = 65.5 kg
Weight lost by Paula (in training) = 3500 grams = 3.5 kg
Paula's weight (after training) =?

65.5 kg - 3.5 kg = 62 kg (Current weight)
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Answer:  f(x) = (x + 3)(x – 7)

Step-by-step explanation:  Use "standard form" of the function and insert values given: vertex (2,-25) intercept point (7,0)

f(x) = a(x-h)² + k   from vertex, h is 2   y is -25   from intercept,  x is 7  f(x) is 0

to find a,  0 = a(7-2)² +(-25)   0 = a(7-2)² -25  add 25 to both sides

25 = a(5)²  25 = 25a  25/25 = a  1=a  (seems useless but verifies implied "a"coefficient is 1)

f(x) = a(x-h)² + k solve to get the quadratic form

f(x) = (x-2)² -25     (x - 2)² is x² -4x +4

f(x) = x² -4x +4 -25  simplify

f(x) = x² -4x - 21   then factor

f(x) = (x + 3)(x - 7)

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2 years ago
Connor has seven more nickels than dimes and twice as many quarters as dimes. If he has $6.20, how many nickels does he have?
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Answer:

The actual number of calories that Mya burned when she

trained for 30 minutes is 240.

Step-by-step explanation:

We have an exponential function that is the best fit for the number of calories Mya burns, in function of time (minutes).

The function is:

y=45.3e^{0.0548x}

Where y: calories burned, and x: training time.

Whenever we use regression models, we have a real value and a predicted value. The difference between them, the measure we want to minimize when we adjust with this typo of models, is called residual.

In the table is shown as one of the columns.

For example, for x=10 minutes, we have a real value of 30 and a predicted value of 78.36, so the residual becomes e=30-78.36=-48.36.

e=y-\hat y=30-78.36=-48.36

For x=30 minutes, we have only the residual, that has a value of 5.53. That means that the predicted value, which we can calculate, is 5.53 below the real value.

The predicted value for x=30 is:

y(30)=45.3e^{0.0548*30}=45.3*5.18=234.47

Using the equation for the residual e, we can calcualte the actual number of calories that Mya burned in 30 minutes:

e=y-\hat y=y-234.47=5.53\\\\y=234.47+5.53\\\\y=240

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