Answer:
The answer is C. As you move closer to the center of the whirlpool, the speed of the current approaches infinity.
This means the closer you get, the faster you go, and the further the distance is the slower the speed. Hope this helps!
(Btw I got this right on the test)
Roper is not using a simple random sample. The samples are calculated to get 500 males and 500 females. This would be very unlikely or improbable to take place in a simple random sample. The design that they are using is a stratified sampling (dividing the population into groups) with 2 strata and these are the males and females.
5/3 = 1.66667
1.666666^3=4.6296 (Volume is measured in cubic units)
54x4.6396=250
250 x pi = 250Pi.
Answer:
first graph is not a function, second graph is a function, 3rd is not enough information, 4th is a function, 5th is not a function, 6th is a function
Step-by-step explanation:
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer