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nlexa [21]
2 years ago
7

If the number of defects found is more than one standard deviation above the mean, the manufacturing facility needs to recalibra

te their machines. What is the probability that the facility needs to recalibrate their machines
Mathematics
1 answer:
Sliva [168]2 years ago
7 0

Answer:

16% probability that the facility needs to recalibrate their machines.

Step-by-step explanation:

We have to use the Empirical Rule to solve this problem.

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

What is the probability that the facility needs to recalibrate their machines?

They will have to recalibrate if the number of defects is more than one standard deviation above the mean.

We know that by the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. The other 100-68 = 32% is more than 1 standard deviation from the mean. Since the normal distribution is symmetric, of those 32%, 16% are more than one standard deviation below the mean, and 16% are more than one standard deviation above the mean.

So there is a 16% probability that the facility needs to recalibrate their machines.

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2 years ago
Which equation represents this number sentence? Two more than one-third of a number is 8
Natali [406]

Answer:

B. 2+\frac{1}{3}n=8

Step-by-step explanation:

Let n be the number.

We are asked to write an mathematical expression for the given word phrase.

One third of a number, n, would be \frac{1}{3}n.

Two more than one third of a number, n, would be 2+\frac{1}{3}n.

We are told that Two more than one-third of a number is 8. We can represent this information in an equation as:

2+\frac{1}{3}n=8

Therefore, option B is the correct choice.

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2 years ago
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A building has an entry the shape of a parabolic arch 74 ft high and 28 ft wide at the base as shown below.
sergiy2304 [10]
The equation of a parabola with vertex at (h,k) is 
y=a(x-h)²+k

vertex isi at (0,0)

y=a(x-0)²+0
y=a(x)²
y=ax²
find a

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x=14 and y=-74

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6 0
2 years ago
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What is the ratio of the area of sector ABC to the area of sector DBE?
shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.


180°= π rad

1° = π/180 rad


For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

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Now ratio,

Area of sector ABC/Area of sector DBE =\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}

= 4/3

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2 years ago
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