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seropon [69]
2 years ago
12

Which expression is equivalent to (4p^-4q)^-2/10pq^-3? Assume p and q do not equal 0. A. 25p^10/4q^8 B. 2q/5p^5 C. p^7q/160 D. 1

25p^11q/2
Mathematics
2 answers:
Naddika [18.5K]2 years ago
8 0
The equivalent expression to 
<span>(4p^-4q)^-2/10pq^-3
</span>=(4^-2p^(-4*-2)q^-2)/(10pq^-3)
=(4^-2p^8q^-2)/(10pq^-3)
=[p^8q^-2/16]/[10pq^-3]
=p^7q/160

Answer: C]<span>p^7q/160</span>
andrew11 [14]2 years ago
7 0

Answer: C. =\frac{p^7q}{160} .


Step-by-step explanation: Given expression \frac{(4p^{-4}q)^{-2}}{10pq^{-3}}.

Applying exponents of exponent rule (ab)^c = a^cb^c and

negative power rule (a)^{n} = \frac{1}{a^n}.

(4p^{-4}q)^{-2} = 4^{-2}p^{-4\times(-2)q^{-2}} = \frac{1\times p^8}{4^2q^2}

= \frac{(4p^{-4}q)^{-2}}{10pq^{-3}}= \frac{1\times p^8q^3}{10\times 4^2pq^2}

= \frac{ p^8q^3}{160pq^2}

Apply quotient rule of exponents \frac{a^m}{a^n} = a^{m-n}.

\frac{ p^8q^3}{160pq^2}= \frac{p^{8-1}q^{3-2}}{160}

=\frac{p^7q}{160} .

Therefore, correct option is C. =\frac{p^7q}{160} .



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6 0
2 years ago
Find any relative extrema of the function. (Round your answers to three decimal places.)
Strike441 [17]

(x) = arcsec(x) − 8x

f'(x) = d/dx( arcsec(x) − 8x )

<span> 1/xsqrt( x^2 - 1) - 8</span>

f'(x) = 0

1/xsqrt( x^2 - 1) - 8 = 0

8 x sqrt (x^2-1) = 1

<span> ( 8 x sqrt (x^2-1) )^2 = 1</span>

64 x^2 ( x^2 - 1) = 1

64 x^4 - 64 x^2 =1

64 x^4 - 64 x^2 - 1 = 0

x = 1.00766 , - 1.00766

<span> x =   - 1.00766</span>

f(- 1.00766) = arcsec(- 1.00766) − 8( - 1.00766)

f( - 1.00766 ) = 11.07949

x = 1.00766

f(1.00766) = arcsec(1.00766) − 8( 1.00766)

f(1.00766 ) = -7.93790

relative maximum (x, y) = (- 1.00766 , 11.07949 ) relative minimum (x, y) = ( 1.00766 , -7.93790  )


8 0
2 years ago
A student is raising money for cancer research. A local business agrees to donate an additional 25% of what the student raises,
bixtya [17]

Answer: 585 maybe??

Step-by-step explanation:

450/100 = 4.5

4,5 = 1 percent of the total amount.

4.5 x 25 = 112.5

112 = 25 percent of 450

4.5 x 5 = 22.5

22.5 = 5 percent of 450

Hope u understand and that this helps:)

4 0
1 year ago
Let f(x)=−3x. The graph of f(x) ​is transformed into the graph of g(x) by a vertical stretch of 4 units and a translation of 4 u
deff fn [24]
<h2>Answer:</h2>

Ques 1)

                   g(x)=-12x+48

Ques 2)

                 g(x)=|3x|+4

<h2>Step-by-step explanation:</h2>

Ques 1)

We know that if a graph is stretched by a factor of a then the transformation if given by:

    f(x) → a f(x)

Also, we know that the translation of a function k units to the right or to the left is given by:

  f(x) →  f(x+k)

where if k>0 then the shift is k units to the left

and if k<0 then the shift is k units to the right.

Here the graph of f(x) ​is transformed into the graph of g(x) by a vertical stretch of 4 units and a translation of 4 units right.

This means that the function g(x) is given by:

g(x)=4f(x-4)\\\\i.e.\\\\g(x)=4(-3(x-4))\\\\i.e.\\\\g(x)=-12(x-4)\\\\i.e.\\\\g(x)=-12x+48

Ques 2)

We know that the transformation of the type:

  f(x) → f(x)+k

is a shift or translation of the function k units up or down depending on k.

If k>0 then the shift is k units up.

and if k<0 then the shift is k units down.

Here, The graph of the function f(x)=|3x| is translated 4 units up.

This means that the transformed function g(x) is given by:

                 g(x)=|3x|+4

4 0
1 year ago
The points (3,9) and (-3,-9) lie in which quadrants?
kumpel [21]

Answer:

Quadrant I and III

Step-by-step explanation:

The coordinate (3,9) is all positive, therefore it lies in quadrant I.

The coordinate (-3,-9) is all negative, therefore it lies in quadrant III.

3 0
2 years ago
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