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a_sh-v [17]
2 years ago
6

Which sample fairly represents the population? Select two options.

Mathematics
2 answers:
Travka [436]2 years ago
8 0

The answers are...

B) calling every third person on the soccer team’s roster to determine how many of the team members have completed their fundraising assignment

E) taking a poll in the lunch room (where all students currently have to eat lunch) to determine the number of students who want to be able to leave campus during lunch

katen-ka-za [31]2 years ago
5 0

Answer:

C! ITS C!!!

Step-by-step explanation:

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You used p minutes one month on your cell phone. The next month you used 75 fewer minutes. Simplify the expression.
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Hi there!

Let's assume that one month is represented by the variable 'm', the amount of minutes you started with is 's', and minutes you spent is 'p'.

So, one month can be represented as 'm=s-p'.

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Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op
Mashcka [7]

Answer:

a) P(X<50)=0.9827

b) P(X>47)=0.4321

c) P(-1.5<z<1.5)=0.8664

Step-by-step explanation:

We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.

a) This means we have to calculate P(x<50).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

z=\dfrac{X-\mu}{\sigma}=\dfrac{50-46.7}{1.75}=\dfrac{3.7}{1.75}=2.114\\\\\\P(X

b) We have to calculatee P(x>47).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

z=\dfrac{X-\mu}{\sigma}=\dfrac{47-46.7}{1.75}=\dfrac{0.3}{1.75}=0.171\\\\\\P(X>47)=P(z>0.171)=0.4321

c) If the value differs 1.5 standard deviations from the mean value, we have a z-score of z=1.5

z=\dfrac{(\mu+1.5\sigma)-\mu}{\sigma}=\dfrac{1.5\sigma}{\sigma}=1.5

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

P(-1.5

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