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2 years ago

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Mrs. Varner deposited q dollars in a bank account that has been earning annual interest. The total value of the account is based

on the function f(x) = q • 1.025x, where x represents the number of years the money has been in the account. If no deposits or withdrawals are made after the initial deposit, which equation represents the total value of the account 5 years from now?

2 answers:

Ray Of Light [21]2 years ago

8 0

The answer is f(x) = q * 1.025<span>x + 5, do you have that?

</span>

babunello [35]2 years ago

8 0

f(x)=q*1.025^x+5 i just took answered the question

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Which is the graph of the system x + 3y > –3 and y < One-halfx + 1?

fenix001 [56]

Answer: THE GRAPH IS ATTACHED.

Step-by-step explanation:

We know that the lines are:

$x + 3y=-3$

$y = \frac{1}{2} x + 1$

Solving for "y" from the first line, we get:

$3y=-x-3\\\\y=-\frac{x}{3}-1$

In order to graph them, we can find the x-intercepts and the y-intercepts.

For the line $x + 3y=-3$ the x-intercepts is:

$0=-\frac{x}{3}-1\\\\(1)(-3)=x\\\\x=-3$

And the y-intercept is:

$y=-\frac{0}{3}-1\\\\y=-1$

For the line $y=\frac{1}{2} x + 1$ the x-intercepts is:

$0=\frac{1}{2} x + 1\\\\-1(2)=x\\\\x=-2$

And the y-intercept is:

$y=\frac{1}{2} (0)+ 1\\\\y=1$

Now we can graph both lines, as you can observe in the image attached (The symbols and $>$ indicates that the lines must be dashed).

By definition, the solution is the intersection region of all the solutions in the system of inequalities.

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2 years ago

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Let C be the closed, piecewise smooth curve formed by traveling in straight lines between the points (-2,1), (-2,-3), (1,-1) , (

Greeley [361]

The given points are the vertices of the quadrilateral

$Q=\left\{(x,y)\mid-2\le x\le1,\dfrac{2x-5}3\le y\le\dfrac{4x+11}3\right\}$

By Green's theorem, the line integral is

$\displaystyle\int_C2xy\,\mathrm dx+xy^2\,\mathrm dy=\iint_Q\frac{\partial(xy^2)}{\partial x}-\frac{\partial(2xy)}{\partial y}\,\mathrm dA$

$=\displaystyle\int_{-2}^1\int_{(2x-5)/3}^{(4x+11)/3}y^2-2x\,\mathrm dy\,\mathrm dx=\boxed{61}$

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2 years ago

Complete the similarity statement for the two triangles shown. Enter your answer in the box. △XBR∼△ Two similar triangles B R X

Andreyy89

Answer:

Here, BRX and NJY are two triangles in which,

BR = 30 cm, RX = 40 cm, BX = 60 cm, NJ = 15 cm, JY = 20 cm and NY = 30 cm,

Also, m∠B = m∠N, m∠R = m∠J and m∠X = m∠Y,

By the property of congruence,

$\angle B \cong \angle N$ , $\angle R \cong \angle J$ and $\angle X \cong \angle Y$

Thus, By AAA similarity postulate,

$\triangle BRX\sim \triangle NJY$

Hence, proved.

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Which is a stretch of an exponential growth function? f(x) = Two-thirds (two-thirds) Superscript x f(x) = Three-halves (two-thir

Arte-miy333 [17]

Answer:

f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Step-by-step explanation:

Since, a function in the form of $f(x) = ab^x$

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

Growth function : If b > 1,

Decay function : if 0 < b < 1,

Since, In

$f(x) =\frac{2}{3}(\frac{2}{3})^x$

$\frac{2}{3} < 1$

Thus, it is a decay function.

in $f(x) =\frac{3}{2}(\frac{2}{3})^x$

$\frac{2}{3} < 1$

Thus, it is a decay function.

in $f(x) =\frac{3}{2}(\frac{3}{2})^x$

$\frac{3}{2} > 1$

Thus, it is a growth function.

in $f(x) =\frac{2}{3}(\frac{3}{2})^x$

$\frac{3}{2} > 1$

Thus, it is a growth function.

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Given the line below.

Yanka [14]

We have to write the equation of the line, in point-slope form. Given an identified point (x1, y1) as the point (-2, 2). So that means x1=-2 and y1=2

Value of slope "m" is not given so i will keep using "m" for the slope. In case value of slope m is given in the problem then you can plug that number in place of m.

Point slope formula is given by:

$y-y_1=m\left(x-x_1\right)$

plug the given values into above formula :

$y-\left(2\right)=m\left(x-\left(-2\right)\right)$

$y-2=m\left(x+2\right)$

so the required answer in point slope form is $y-2=m\left(x+2\right)$

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2 years ago