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Ganezh [65]
2 years ago
13

A bag contains 15 15 red candies, 15 15 yellow candies, and 15 15 blue candies. what is the probability of randomly choosing two

candies of the same color, without replacement?
Mathematics
2 answers:
Wittaler [7]2 years ago
4 0
Based on my calculations, this would be 10%.
Sav [38]2 years ago
3 0

Answer:

\texttt{Probability of choosing two candies of the same color}=\frac{7}{22}

Step-by-step explanation:

Probability of choosing two candies of the same color = Probability of choosing 2 red candies + Probability of choosing 2 yellow candies + Probability of choosing 2 blue candies.

Number of total candies = 15+15+15 = 45

Number of red candies = 15

\texttt{Probability of choosing 2 red candies}=\frac{15}{45}\times \frac{14}{44}=\frac{1}{3}\times \frac{7}{22}=\frac{7}{66}

Number of yellow candies = 15

\texttt{Probability of choosing 2 yellow candies}=\frac{15}{45}\times \frac{14}{44}=\frac{1}{3}\times \frac{7}{22}=\frac{7}{66}

Number of blue candies = 15

\texttt{Probability of choosing 2 blue candies}=\frac{15}{45}\times \frac{14}{44}=\frac{1}{3}\times \frac{7}{22}=\frac{7}{66}

\texttt{Probability of choosing two candies of the same color}=\frac{7}{66}+\frac{7}{66}+\frac{7}{66}\\\\\texttt{Probability of choosing two candies of the same color}=\frac{7}{22}

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To earn extra money a month
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2 years ago
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A rancher owns a rectangular piece of land that is 4.1 mi long and 2.5 mi wide. Find the units for the perimeter of the rectangl
Naddik [55]

Answer:

13.1mi

Step-by-step explanation:

Length(l) = 4.1mi

Breadth(b) = 2.5 mi

Perimeter of a rectangle = addition of all sides that is = l + l + b + b as a rectangle has 2 opposite equal length and also breadth.

Therefore perimeter = 4.1 + 4.1 + 2.5 + 2.5

= 8.1 + 5

=13.1 mi

I hope this was helpful, Please mark as brainliest

8 0
2 years ago
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8 persons attended an interview at a company where each person can be either selected or rejected. find the number of ways of an
Ganezh [65]
2 possibilities for each person, for 8 people
= 2*2*2*2*2*2*2*2
=2^8
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2 years ago
Which of the following accurately compare 15-√105 and 5?
Vlad [161]
The answer is c. I hope that helps
7 0
2 years ago
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In a standard game of pool, there are 15 balls labeled 1 through 15. a) In how many ways can the 15 balls be ordered? (5 points)
katovenus [111]

Answer:

<h2>a) 1.308*10¹² ways</h2><h2>b) 455 way</h2>

Step-by-step explanation:

If  there are 15 balls labeled 1 through 15 in a standard football game, the order of arrangement of the 15 balls can be done in 15! ways.

15! = 15*14*13*12*11*10*9*8*7*6*5*4*3*2

15! = 1.308*10¹² ways

b)  If 3 of the 15 balls are to be chosen if order does not matter, this can be done in 15C3 number of ways. Since we are selecting some balls out of the total number of balls, we will use the concept of combination.

Using the combination formula nCr = n!/(n-r)!r!

15C3 = 15!/(15-3)!3!

15C3 = 15!/12!3!

15C3 = 15*14*13*12!/12!*6

15C3 = 15*14*13/6

15C3 = 455 ways

7 0
2 years ago
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