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Verizon [17]
2 years ago
10

Find the simplified product b-5/2b x b^2+3b/b-5

Mathematics
2 answers:
White raven [17]2 years ago
8 0

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Masteriza [31]2 years ago
6 0

Your answer should be A

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valina [46]
Here, Hope this helps,

6 0
2 years ago
Hariette would like to review the income and expenses that were actually paid last month so she can determine how much to set as
Brrunno [24]

Answer:

Hybrid basis

Step-by-step explanation:

There are different methods of accounting used by businesses depending on their peculiar needs. Below are the type of accounting methods:

- Cash basis is when revenues and expenses are recognised when cash is recieved or paid out.

-Accrual basis is when revenue and expenses are recognised when they are earned. For example if services are rendered to a client that will pay in a week's time, since service has already been given it is considered that the future payment has been earned.

- Modified basis combines elements of cash and accrual basis. For example considering short term assets like accounts receivable and accounts payable as cash items. Long term assets are recorded on accrual basis.

- Hybrid basis is used when cash and accrual methods are used for various expenses and tax. Mostly it is used for internal accounting purposes.

In this scenario Hariette would like to review the income and expenses that were actually paid last month. This requires a cash basis that shows actual amount recieved and paid last month. Account receivable and payable are not considered.

In setting aside money for tax she will employ accrual basis accounting. It is an expense that is estimated for future use.

So the hybrid basis is the method that will be most suitable.

5 0
2 years ago
Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 140 cards,
hjlf

Answer:

a) 0.9644 or 96.44%

b) 0.5429 or 54.29%

Step-by-step explanation:

a) The probability that at least 1 defective card is in the sample P(A) = 1 - probability that no defective card is in the sample P(N)

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 20

Total number of non defective cards = 140-20 = 120

P(N) = Number of possible selections of 20 non defective cards ÷ Number of possible selections of 20 cards from all the cards.

P(N) = 120C20/140C20 = 0.0356

From equation 1

P(A) = 1 - 0.0356

P(A) = 0.9644 or 96.44%

b) Using the same method as a) above

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 5

Total number of non defective cards = 140-5 = 135

P(N) = 135C20/140C20 = 0.457

From equation 1

P(A) = 1 - 0.4571

P(A) = 0.5429 or 54.29%

8 0
2 years ago
On your last credit card statement, you had a previous balance of $98.14, payments of $10, a periodic rate of 1.34 percent, and
Valentin [98]
The correct answer is D
3 0
2 years ago
Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFract
serg [7]

Answer:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Step-by-step explanation:

Given:

The equation to solve is given as:

x^2=-5x+8

Rearrange the given equation in standard form ax^2+bx +c =0, where, a,\ b,\ and\ c are constants.

Therefore, we add 5x-8 on both sides to get,

x^2+5x-8=0

Here, a=1,b=5,c=-8

The solution of the above equation is determined using the quadratic formula which is given as:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plug in a=1,b=5,c=-8 and solve for x.

x=\frac{-5\pm \sqrt{5^2-4(1)(-8)}}{2(1)}\\x=\frac{-5\pm \sqrt{25+32}}{2}\\x=\frac{-5\pm \sqrt{57}}{2}\\\\\\\therefore x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Therefore, the solutions are:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

4 0
2 years ago
Read 2 more answers
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