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2 years ago

Two unique letters are chosen at random from the alphabet.

2 answers:

7 0

A - choosing letter A first

$|\Omega|=P(26,2)=\dfrac{26!}{24!}=25\cdot26\\
|A|=1\cdot25=25\\\\
P(A)=\dfrac{25}{25\cdot26}=\dfrac{1}{26}\approx0.0385$

Tamiku [17]2 years ago

4 0

Answer:

A 0.0385

Step-by-step explanation:

There are in total 26 letters in English alphabet

Two unique letters are chosen at random.

I letter can be taken from any one of the 26 hence

probability for I letter to be a out of 26 letters = 1/26

We can convert this into decimal as

Probability that the first letter chosen is A =0.0385

Option A is right answer.

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Given that:

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Fish are green swordtails male = 36

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$\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}$

$\text{P(green swordtail)}=\dfrac{80}{140}$

$\text{P(green swordtail)}=\dfrac{4}{7}$

Therefore, the probability that the selected fish is a green swordtail is $\dfrac{4}{7}.$

B. We have to find the probability that the selected fish is male.

$\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}$

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$\text{P(Male fish)}=\dfrac{60}{140}$

$\text{P(Male fish)}=\dfrac{3}{7}$

Therefore, the probability that the selected fish is a male, is $\dfrac{3}{7}.$

C. We have to find the probability that the selected fish is a male green swordtail.

$\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}$

$\text{P(Male green swordtail)}=\dfrac{36}{140}$

$\text{P(Male green swordtail)}=\dfrac{9}{35}$

Therefore, probability that the selected fish is a male green swordtail is $\dfrac{9}{35}.$

We have to find the probability that the selected fish is either a male or a green swordtail.

$\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}$

$\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}$

$\text{P(Male or green swordtail)}=\dfrac{96}{140}$

$\text{P(Male or green swordtail)}=\dfrac{24}{35}$

Therefore, the probability the selected fish is either a male or a green swordtail is $\dfrac{24}{35}.$

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