I'm pretty sure the answer will be 6/10
Hope this helps, best of luck, terribly sorry if I'm wrong if I am my apologies
~Animaljamissofab ♥
Table is attached below
From the table we can see that the Lemon cost is equal to 35% of the expenses
Let the expense be x, Lemons cost is 70
Lemon cost = 35% * x
70 = 35% * x ( 35% = 
= 0.35)
70 = 0.35 * x
x = 
x= 200, Expense = $200
Given : Profit percentage is 15%= 
= 0.15
Profit = profit percentage * Expense
Profit = 0.15 * 200 = 30
So profit = $30
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work
EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same
For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y
For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4
Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.
Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the
x²y = -4 ... (I)
Condition 2: Real parts are the same
x² + y = -3 ... (II)
We have a system of equations since both conditions must be satisfied
x²y = -4 ... (I)
x² + y = -3 ... (II)
We can rearrange equation (II) so that we have
y = -3 - x² ... (II)
Substituting into equation (I)
x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0
Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.
Solve for y:
y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4
So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:
-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i
x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i
They result in conjugates
Answer:
- <em>Between which two tens does it fall?</em><em> </em><u>Between 25 and 26 tens</u>
<em><u /></em>
- <em>Between which two hundreds does it fall?</em> <u>Between 2 and 3 hundreds</u>
Explanation:
The place-value chart is:
Hundreds Tens Ones
2 5 3
<em><u /></em>
<em><u>a) Between which two tens does it fall? </u></em>
Using the place values you can write 253 = 25 × 10 + 3, i.e. 25 tens and 3 ones.
From that you can write:
Then, you conclude that 253 is between 25 and 26 tens.
<u><em>b) Between which two hundreds does it fall?</em></u>
Using the same reasoning:
- 253 = 2 × 100 + 5 × 10 + 3 = 253
Conclusion: 253 is between 2 hundreds and 3 hundreds.
