Answer:
a) f(-1/2) = -2 is NOT TRUE.
b) f(0) =3/2 is TRUE.
c) f(1) = -1 is NOT TRUE.
d) f(2) = 1 is NOT TRUE.
e) f(4) = 7/2 is TRUE.
Step-by-step explanation:
Here, the given function is 
Now, checking for each values for the given function:
a) Putting x = (-1/2):
and (5/4) ≠ -2
Hence, f(-1/2) = -2 is NOT TRUE.
b)Putting x = 0 :
Hence, f(0) =3/2 is TRUE.
c) Putting x = 1:
Hence, f(1) = -1 is NOT TRUE.
d)Putting x = 2:
and (5/2) ≠ 1
Hence, f(2) = 1 is NOT TRUE.
e)Putting x = 4:
Hence, f(4) = 7/2 is TRUE.
Area = perimeter + 132.
Let each side of the city be x miles long, then:-
x^2 = 4x + 132
x^2 - 4x - 132 = 0
x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2
x = 13.66, -9.66 We ignore the negative
So the city has dimension of 13.66 * 13.66
13.7 * 13.7 to nearest 10th
Answer:
Step-by-step explanation:
The only answer that makes any sense is B. A commission works on the premise that the more you sell, the more money you take home.
Suppose a car salesman working at a GM dealership is working on a salary of 10% of the selling price. (A bit high).
Suppose on one month he sells 10 trucks, each one selling for 40000 dollars.
1 truck brings in 40000*10/100 = 4000 for the salesman.
10 trucks bring in 10*4000 = 40000 dollars.
The next month he only sells 8 Trucks. His commission is
40000 * 10/100 = 4000 per truck
8 trucks * 4000 = 32000 total for that month. A little less but it's quite a bit for a month's work all the same.
Answer:
0
Step-by-step explanation:
We have the fraction 
Step 1. Use LCM of the fraction, (2m+3)(2m-3), to simplify the fraction:
![\frac{(2m-3)(2m)-(2m+3)(2m)}{(2m+3)(2m-3)} =\frac{2m^2-6m-[2m^2+6m]}{(2m+3)(2m-3)} =\frac{2m^2-6m-2m^2-6m}{(2m+3)(2m-3)} =\frac{-12m}{(2m+3)(2m-3)}](https://tex.z-dn.net/?f=%5Cfrac%7B%282m-3%29%282m%29-%282m%2B3%29%282m%29%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B2m%5E2-6m-%5B2m%5E2%2B6m%5D%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B2m%5E2-6m-2m%5E2-6m%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B-12m%7D%7B%282m%2B3%29%282m-3%29%7D)
Step 2. Equate the resulting fraction to zero and solve for 
:
![-12m=0[(2m+3)(2m-3)]](https://tex.z-dn.net/?f=-12m%3D0%5B%282m%2B3%29%282m-3%29%5D)
Step 3. Replace the value in the original equation and check if it holds:
Since ,
Since the only solution of the equation holds, the equation bellow doesn't have any extraneous solution
Answer:
A. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.
